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If A is a matrix of order 3xx3, then |3A...

If `A` is a matrix of order `3xx3`, then `|3A|` is equal to………

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To solve the problem of finding \(|3A|\) where \(A\) is a \(3 \times 3\) matrix, we can use the property of determinants related to scalar multiplication of matrices. Here’s the step-by-step solution: ### Step 1: Understand the property of determinants For any \(n \times n\) matrix \(A\) and a scalar \(k\), the determinant of the matrix \(kA\) is given by the formula: \[ |kA| = k^n |A| \] where \(n\) is the order of the matrix. ### Step 2: Identify the order of the matrix In this case, the matrix \(A\) is of order \(3 \times 3\), which means \(n = 3\). ### Step 3: Substitute the values into the formula We need to find \(|3A|\). Using the property identified in Step 1, we substitute \(k = 3\) and \(n = 3\): \[ |3A| = 3^3 |A| \] ### Step 4: Calculate \(3^3\) Now, calculate \(3^3\): \[ 3^3 = 27 \] ### Step 5: Write the final result Thus, we can express \(|3A|\) as: \[ |3A| = 27 |A| \] ### Conclusion The determinant \(|3A|\) is equal to \(27\) times the determinant of \(A\).

To solve the problem of finding \(|3A|\) where \(A\) is a \(3 \times 3\) matrix, we can use the property of determinants related to scalar multiplication of matrices. Here’s the step-by-step solution: ### Step 1: Understand the property of determinants For any \(n \times n\) matrix \(A\) and a scalar \(k\), the determinant of the matrix \(kA\) is given by the formula: \[ |kA| = k^n |A| \] where \(n\) is the order of the matrix. ...
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Knowledge Check

  • Let A a non singular square matrix of order 3xx3 . Then |adjA| is equal to

    A
    `|A|`
    B
    `|A|^(2)`
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    `|A|^(3)`
    D
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  • Let A be a square matrix of order 3 times 3 , then abs(kA) is equal to

    A
    `kabs(A)`
    B
    `k^(2)abs(A)`
    C
    `k^(3)abs(A)`
    D
    `3kabs(A)`
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