For what value of `k` is the following function continuous at `x=2?` `f(x)={2x+1; x<2 k ; x=2 3x-1; x >2}`

Explanation

To determine the value of \( k \) that makes the function \( f(x) \) continuous at \( x = 2 \), we need to ensure that the following condition holds:

\[ \lim_{x \to 2^-} f(x) = f(2) = \lim_{x \to 2^+} f(x) \]

Given the function:

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