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Calculate the emf of the following cell ...

Calculate the emf of the following cell at `25^(@)C : Ag(s)| Ag^(+)(10^(-3)M)||Cu^(2+)(10^(-1)M)|Cu(s)" Give "E_("cell")^(@)=-0.46 V and log 10^(n)=n`

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AI Generated Solution

To calculate the EMF of the given cell at 25°C, we will follow these steps: ### Step 1: Identify the half-reactions For the cell representation `Ag(s)| Ag^(+)(10^(-3)M)||Cu^(2+)(10^(-1)M)|Cu(s)`, we identify the half-reactions occurring at the cathode and anode. - **Cathode Reaction (Reduction):** \[ Cu^{2+}(aq) + 2e^- \rightarrow Cu(s) ...
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Calculate the emf of the following cell at 25^(@)C Ag(s)|AgNO_(3) (0.01 M)||AgNO_(3) (0.05 M)|Ag (s)

(a) What is limiting molar conductivity ? Why there is step rise in the molar conductivity of weak electrolyte on dilution ? (b) Calculate the emf of the following cell at 298 K : Mg(s) |Mg^(2+)(0.1 M)||Cu^(2+)(1.0 xx 10^(-3)M)|Cu(s) [Given : E_("cell")^(@) = 2.71 V]

Knowledge Check

  • Calculate the emf of the following concentration cell at 25^(@)C : Ag(s)|AgNO_(3) (0.01 M)||AgNO_(3) (0.05 M)|Ag (s)

    A
    0.828V
    B
    0.0413V
    C
    `-0.0413` V
    D
    `-0.828` V

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