Write the structure of the following :
(i) `BrF_(3)` (ii) `XeF_(4)`

Explanation

To determine the structures of \( \text{BrF}_3 \) and \( \text{XeF}_4 \), we will follow a systematic approach by considering the valence electrons, hybridization, and molecular geometry.

### Step 1: Determine the Valence Electrons
- **Bromine (Br)** is in Group 17 and has 7 valence electrons.
- **Fluorine (F)** is also in Group 17 and has 7 valence electrons.

For \( \text{BrF}_3 \):
- Total valence electrons = 7 (from Br) + 3 × 7 (from 3 F) = 7 + 21 = 28 electrons.
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