Home
Class 12
CHEMISTRY
Given reasons : (i) Zn is not regarded ...

Given reasons :
(i) Zn is not regarded as a transition element.
(ii) `Cr^(2+)` is a strong reducing agent.

Text Solution

Verified by Experts

(i) Zn belongs too d block but not considered as transition elements because it contains completely filled 3d orbital and fo not show properties like other transition elements.
(ii) `Cr^(2+)` has the configuration `3d^(4).` It can blse electron to from `Cr^(3+)` which has stable `3d^(3)` configuration. Hence, it is strong reducing agent.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • XII BOARDS

    XII BOARD PREVIOUS YEAR PAPER ENGLISH|Exercise [SET-1]|36 Videos

  • XII BOARDS

    XII BOARD PREVIOUS YEAR PAPER ENGLISH|Exercise Outside Delhi: Set-II|11 Videos

  • XII BOARDS

    XII BOARD PREVIOUS YEAR PAPER ENGLISH|Exercise [OUTSIDE DELHI : SET -III]|10 Videos

  • SAMPLE PAPER 2019

    XII BOARD PREVIOUS YEAR PAPER ENGLISH|Exercise SECTION: D|1 Videos

Similar Questions

Explore conceptually related problems

Explain the following observations : (i) Copper atom has completely field d orbitals (3d^(10)) in its ground state, it is regarded as a transition element. (ii) Cr^(2+) is a stronger reducing agent than Fe^(2+) in aqueous solutions.

Why is zinc not regarded as a transition element ? (At. No. Zn = 30)

Knowledge Check

  • The incorrect statement regarding transition elements is

    A
    They have low tensile strength
    B
    Their melting and boiling points are very high
    C
    They are good conductors of heat
    D
    Their density is very high.

    • Similar Questions

    Explore conceptually related problems

    Sodium acts as a strong reducing agent. Why?

    Alkali metals are strong reducing agents because

    Why s-block elements act as strong reducing agents ?

    Assertion: Cl_(2) gas belaches the articles permanently. Reason: Cl_(2) is a strong reducing agent.

    (a) Account for the following : (i) Mn shows the highest oxidation state of +7 with oxygen but with fluorine it shows the highest oxidation state of +4. (ii) Cr^(2+) is a strong reducing agent. (iii) Cu^(2+) salts are coloured while Zn^(2+) salts are white. (b) Complete the following equations : (i) 2MnO_(2) + 4KOH + O_(2) overset(Delta)(to) (ii) Cr_(2)O_(7)^(2-) + 14H^(+)6I^(-) to

    Choose the correct statement regarding transition elements?

    (a) Complete the following chemical equations: (i) Cr_(2) O_(7)^(2-) (aq) + H_(2) S(g) + H^(+) (aq) to (ii) Cu^(2+)(aq) + I^(-) (aq) to (b) How would you account for the following : (i) The oxidising power of oxoanions are in the order VO_(2)^(+) lt Cr_(2)O_(7)^(2-) lt Mn O_(4)^(-) (ii) The third ionization enthalpy of manganess (Z = 25) is exceptionally high. (iii) Cr^(2+) is a stronger reducing agent than Fe^(2+) .

    Home
    Profile