(a) Draw the structures of the following compounds :
(i) `XeF_(4)`
(ii) `N_(2)O_(5)`.

Explanation

### Step-by-Step Solution:

#### (i) Structure of `XeF4` (Xenon Tetrafluoride)

1. **Determine the central atom**: The central atom in `XeF4` is xenon (Xe).
2. **Count the valence electrons**: Xenon has 8 valence electrons, and each fluorine (F) has 7 valence electrons. Since there are 4 fluorine atoms, the total number of valence electrons contributed by fluorine is 4 × 7 = 28. Therefore, the total number of valence electrons in `XeF4` is 8 + 28 = 36.
3. **Draw the skeletal structure**: Place the xenon atom in the center and surround it with 4 fluorine atoms.
4. **Form bonds**: Each fluorine atom forms a single bond with the xenon atom. This uses 4 pairs of electrons (8 electrons).
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