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The angle between the pair of lines whos...

The angle between the pair of lines whose equation is `4x^(2)+10xy+my^(2)+5x+10y=0`, is

A

`tan^(-1)(3//8)`

B

`tan^(-1)(3//4)`

C

`tan^(-1){2sqrt(25-4m//)(m+4)},m in R`

D

None of these

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To find the angle between the pair of lines represented by the equation \(4x^2 + 10xy + my^2 + 5x + 10y = 0\), we will follow these steps: ### Step 1: Identify coefficients The general form of the equation of a pair of straight lines is given by: \[ ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0 \] From the given equation, we can identify the coefficients: - \(a = 4\) - \(b = m\) - \(c = 0\) - \(g = 5\) - \(f = 5\) - \(h = 5\) ### Step 2: Apply the condition for a pair of straight lines For the equation to represent a pair of straight lines, the following condition must hold: \[ abc + 2fgh - a f^2 - b g^2 - c h^2 = 0 \] Substituting the identified coefficients into this condition: \[ 4 \cdot m \cdot 0 + 2 \cdot 5 \cdot 5 \cdot 5 - 4 \cdot 5^2 - m \cdot (5/2)^2 - 0 \cdot 5^2 = 0 \] This simplifies to: \[ 0 + 250 - 100 - \frac{25m}{4} = 0 \] Thus, we have: \[ 250 - 100 - \frac{25m}{4} = 0 \] ### Step 3: Solve for \(m\) Rearranging the equation gives: \[ 150 = \frac{25m}{4} \] Multiplying both sides by 4: \[ 600 = 25m \] Dividing by 25: \[ m = 24 \] ### Step 4: Calculate the angle between the lines Now that we have \(m\), we can find the angle between the lines using the formula: \[ \tan \theta = \frac{2\sqrt{h^2 - ab}}{a + b} \] Substituting \(a = 4\), \(b = 24\), and \(h = 5\): \[ \tan \theta = \frac{2\sqrt{5^2 - (4)(24)}}{4 + 24} \] Calculating inside the square root: \[ \tan \theta = \frac{2\sqrt{25 - 96}}{28} \] This simplifies to: \[ \tan \theta = \frac{2\sqrt{-71}}{28} \] Since the value under the square root is negative, it indicates that the angle is complex, implying that the lines do not intersect in the real plane. ### Final Result Thus, the angle between the pair of lines is complex, and we can express it in terms of the imaginary unit \(i\): \[ \tan \theta = \frac{2i\sqrt{71}}{28} = \frac{i\sqrt{71}}{14} \]

To find the angle between the pair of lines represented by the equation \(4x^2 + 10xy + my^2 + 5x + 10y = 0\), we will follow these steps: ### Step 1: Identify coefficients The general form of the equation of a pair of straight lines is given by: \[ ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0 \] From the given equation, we can identify the coefficients: ...
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