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Find the equation of the right bisector ...

Find the equation of the right bisector of the line segment joining the points (3,4) and (-1,2).

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To find the equation of the right bisector of the line segment joining the points (3, 4) and (-1, 2), we will follow these steps: ### Step 1: Find the Midpoint of the Line Segment The midpoint \( M \) of the line segment joining the points \( A(3, 4) \) and \( B(-1, 2) \) can be calculated using the midpoint formula: \[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \] Substituting the coordinates of points \( A \) and \( B \): \[ M = \left( \frac{3 + (-1)}{2}, \frac{4 + 2}{2} \right) = \left( \frac{2}{2}, \frac{6}{2} \right) = (1, 3) \] ### Step 2: Find the Slope of Line Segment AB Next, we find the slope \( m_{AB} \) of the line segment \( AB \) using the slope formula: \[ m_{AB} = \frac{y_2 - y_1}{x_2 - x_1} \] Substituting the coordinates of points \( A \) and \( B \): \[ m_{AB} = \frac{2 - 4}{-1 - 3} = \frac{-2}{-4} = \frac{1}{2} \] ### Step 3: Find the Slope of the Right Bisector The slope of the right bisector \( m_{CD} \) is the negative reciprocal of the slope of line segment \( AB \): \[ m_{CD} = -\frac{1}{m_{AB}} = -\frac{1}{\frac{1}{2}} = -2 \] ### Step 4: Use the Point-Slope Form to Find the Equation of the Right Bisector Now, we can use the point-slope form of the equation of a line, which is given by: \[ y - y_1 = m(x - x_1) \] Here, \( (x_1, y_1) \) is the midpoint \( (1, 3) \) and \( m = -2 \): \[ y - 3 = -2(x - 1) \] Expanding this equation: \[ y - 3 = -2x + 2 \] \[ y + 2x = 5 \] ### Final Equation Thus, the equation of the right bisector of the line segment joining the points (3, 4) and (-1, 2) is: \[ y + 2x = 5 \] ---

To find the equation of the right bisector of the line segment joining the points (3, 4) and (-1, 2), we will follow these steps: ### Step 1: Find the Midpoint of the Line Segment The midpoint \( M \) of the line segment joining the points \( A(3, 4) \) and \( B(-1, 2) \) can be calculated using the midpoint formula: \[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \] Substituting the coordinates of points \( A \) and \( B \): ...
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CENGAGE ENGLISH-STRAIGHT LINES-CONCEPT APPLICATION EXERCISE 2.1
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  2. about to only mathematics

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  15. One side of a rectangle lies along the line 4x+7y+5=0. Two of its vert...

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