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If the coordinates of the vertices of tr...

If the coordinates of the vertices of triangle `A B C` are `(-1,6),(-3,-9)` and `(5,-8)` , respectively, then find the equation of the median through `Cdot`

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To find the equation of the median through vertex C of triangle ABC with vertices A(-1, 6), B(-3, -9), and C(5, -8), we will follow these steps: ### Step 1: Find the midpoint of side AB The midpoint \( P \) of line segment \( AB \) can be calculated using the midpoint formula: \[ P\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) \] where \( A(-1, 6) \) and \( B(-3, -9) \). Calculating the coordinates of \( P \): \[ P\left(\frac{-1 + (-3)}{2}, \frac{6 + (-9)}{2}\right) = P\left(\frac{-4}{2}, \frac{-3}{2}\right) = P(-2, -\frac{3}{2}) \] ### Step 2: Find the slope of line segment PC Next, we need to find the slope of the line segment \( PC \). The slope \( m \) can be calculated using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] where \( P(-2, -\frac{3}{2}) \) and \( C(5, -8) \). Calculating the slope: \[ m = \frac{-8 - \left(-\frac{3}{2}\right)}{5 - (-2)} = \frac{-8 + \frac{3}{2}}{5 + 2} = \frac{-\frac{16}{2} + \frac{3}{2}}{7} = \frac{-\frac{13}{2}}{7} = -\frac{13}{14} \] ### Step 3: Write the equation of line PC Using the point-slope form of the equation of a line: \[ y - y_1 = m(x - x_1) \] where \( (x_1, y_1) = (5, -8) \) and \( m = -\frac{13}{14} \). Substituting the values: \[ y - (-8) = -\frac{13}{14}(x - 5) \] This simplifies to: \[ y + 8 = -\frac{13}{14}x + \frac{65}{14} \] Rearranging gives: \[ y = -\frac{13}{14}x + \frac{65}{14} - 8 \] Converting \( 8 \) into a fraction with a denominator of 14: \[ y = -\frac{13}{14}x + \frac{65}{14} - \frac{112}{14} \] This simplifies to: \[ y = -\frac{13}{14}x - \frac{47}{14} \] ### Step 4: Convert to standard form To convert this equation into standard form \( Ax + By + C = 0 \): \[ \frac{13}{14}x + y + \frac{47}{14} = 0 \] Multiplying through by 14 to eliminate the fraction: \[ 13x + 14y + 47 = 0 \] ### Final Answer The equation of the median through vertex C is: \[ 13x + 14y + 47 = 0 \]

To find the equation of the median through vertex C of triangle ABC with vertices A(-1, 6), B(-3, -9), and C(5, -8), we will follow these steps: ### Step 1: Find the midpoint of side AB The midpoint \( P \) of line segment \( AB \) can be calculated using the midpoint formula: \[ P\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) \] where \( A(-1, 6) \) and \( B(-3, -9) \). ...
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