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g(x+y)=g(x)+g(y)+3xy(x+y)AA x, y in R" a...

`g(x+y)=g(x)+g(y)+3xy(x+y)AA x, y in R" and "g'(0)=-4.`
The value of g'(1) is

A

0

B

1

C

-1

D

none of these

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To solve the problem, we will follow these steps: ### Step 1: Differentiate the given functional equation We start with the equation: \[ g(x+y) = g(x) + g(y) + 3xy(x+y) \] We will differentiate both sides with respect to \( x \) while treating \( y \) as a constant. ...
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