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A tangent is drawn at any point on the h...

A tangent is drawn at any point on the hyperbola `(x^(2))/(a^(2))-(y^(2))/(b^(2)) =1`. If this tangent is intersected by the tangents at the vertices at points P and Q, then which of the following is/are true

A

S,S',P and Q are concyclic

B

PQ is diameter of the circle

C

S,S', P and Q forms rhombus

D

PQ is diagonal of acute angle of the rhombus formed by S,S',P and Q

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To solve the problem step by step, we will analyze the given hyperbola and the tangents drawn at its vertices, and then determine the conditions under which the points P and Q are concyclic. ### Step 1: Write the equation of the hyperbola The given hyperbola is: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] ### Step 2: Write the equation of the tangent at a point on the hyperbola The equation of the tangent to the hyperbola at a point \((x_0, y_0)\) can be expressed as: \[ \frac{xx_0}{a^2} - \frac{yy_0}{b^2} = 1 \] For a point on the hyperbola, we can parameterize it as: \[ x_0 = a \sec \theta, \quad y_0 = b \tan \theta \] Thus, the equation of the tangent becomes: \[ \frac{x(a \sec \theta)}{a^2} - \frac{y(b \tan \theta)}{b^2} = 1 \] Simplifying this gives: \[ \sec \theta \cdot x - \frac{b}{a} \tan \theta \cdot y = 1 \] ### Step 3: Determine the vertices of the hyperbola The vertices of the hyperbola are located at: \[ S(a, 0) \quad \text{and} \quad S'(-a, 0) \] ### Step 4: Write the equations of the tangents at the vertices The tangents at the vertices \(S\) and \(S'\) are horizontal lines given by: 1. At \(S(a, 0)\): \(y = 0\) 2. At \(S'(-a, 0)\): \(y = 0\) ### Step 5: Find the intersection points P and Q The tangent line intersects the x-axis at points P and Q. The coordinates of P and Q can be found by substituting \(y = 0\) into the tangent equation: \[ \sec \theta \cdot x - 0 = 1 \implies x = \cos \theta \] So, the points where the tangent intersects the x-axis are: \[ P(a, b \tan \frac{\theta}{2}) \quad \text{and} \quad Q(-a, -b \cot \frac{\theta}{2}) \] ### Step 6: Check if points P, Q, S, and S' are concyclic To check if the points \(P\), \(Q\), \(S\), and \(S'\) are concyclic, we can use the condition that the product of the lengths from the center to the points must be equal: \[ OS \cdot OS' = OP \cdot OQ \] Where \(O\) is the origin. ### Step 7: Calculate distances 1. \(OS = a\) 2. \(OS' = a\) 3. \(OP = \sqrt{a^2 + (b \tan \frac{\theta}{2})^2}\) 4. \(OQ = \sqrt{a^2 + (-b \cot \frac{\theta}{2})^2}\) ### Step 8: Verify the condition Using the distances calculated, we can verify if: \[ OS \cdot OS' = OP \cdot OQ \] This will lead to the conclusion that the points are concyclic if the equality holds. ### Conclusion Thus, we conclude that the points \(S\), \(S'\), \(P\), and \(Q\) are concyclic if the derived conditions are satisfied.

To solve the problem step by step, we will analyze the given hyperbola and the tangents drawn at its vertices, and then determine the conditions under which the points P and Q are concyclic. ### Step 1: Write the equation of the hyperbola The given hyperbola is: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] ...
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