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If one end of the diameter of the circle...

If one end of the diameter of the circle `2x^2+2y^2-4x-8y+2=0` is (3,2), then find the other end of the diameter.

Text Solution

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The correct Answer is:
(-1,2)
The center of the given circle is (1,2). Let (alpha,beta)` be the other end. Then,
`=2 sqrt(g^(2)-c)=2 sqrt(25-9)=8`
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