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If one end of the diameter of the circle...

If one end of the diameter of the circle `2x^2+2y^2-4x-8y+2=0` is (3,2), then find the other end of the diameter.

Text Solution

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The correct Answer is:
(-1,2)
The center of the given circle is (1,2). Let (alpha,beta)` be the other end. Then,
`=2 sqrt(g^(2)-c)=2 sqrt(25-9)=8`
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Knowledge Check

  • If one end of a diameter of the circle x^(2) + y^(2) - 4x - 6y + 11 = 0 is (3, 4), then the coordinates of the other end of the diameter are

    A
    (a) (2,1)
    B
    (b) (-2,1)
    C
    (c) (1,2)
    D
    (d) (-1,-2)

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