Home
Class 12
MATHS
ABCD is a parallelogram. L is a point on...

ABCD is a parallelogram. L is a point on BC which divides BC in the ratio `1:2`. AL intersects BD at P. M is a point on DC which divides DC in the ratio `1 : 2` and AM intersects BD in Q.
Point P divides AL in the ratio

A

`1:2`

B

`1:3`

C

`3:1`

D

`2:1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the ratio in which point P divides line segment AL in the given parallelogram ABCD. Here’s a step-by-step solution: ### Step 1: Understand the Geometry We have a parallelogram ABCD. Point L divides side BC in the ratio 1:2, and point M divides side DC in the ratio 1:2. We need to find the ratio in which point P divides line segment AL, where AL intersects BD at point P. ### Step 2: Assign Coordinates To simplify the calculations, we can assign coordinates to the points: - Let A = (0, 0) - Let B = (a, 0) - Let C = (a + b, c) - Let D = (b, c) ### Step 3: Find Coordinates of Points L and M Since L divides BC in the ratio 1:2: - The coordinates of L can be calculated using the section formula: \[ L = \left( \frac{2(a + b) + 1a}{1 + 2}, \frac{2c + 0}{1 + 2} \right) = \left( \frac{2a + 2b + a}{3}, \frac{2c}{3} \right) = \left( \frac{3a + 2b}{3}, \frac{2c}{3} \right) \] For point M, which divides DC in the ratio 1:2: - The coordinates of M can be calculated similarly: \[ M = \left( \frac{2b + 1(a + b)}{1 + 2}, \frac{2c + 0}{1 + 2} \right) = \left( \frac{2b + a + b}{3}, \frac{2c}{3} \right) = \left( \frac{a + 3b}{3}, \frac{2c}{3} \right) \] ### Step 4: Find the Equations of Lines AL and BD - The line AL can be represented by the equation derived from points A and L. - The line BD can be represented by the equation derived from points B and D. ### Step 5: Find the Intersection Point P To find point P, we solve the equations of lines AL and BD simultaneously. This will give us the coordinates of point P. ### Step 6: Determine the Ratio AP:PL Using the coordinates of points A, L, and P, we can find the lengths AP and PL. The ratio AP:PL can be calculated as: \[ \text{Ratio} = \frac{AP}{PL} \] ### Step 7: Conclusion After calculating the lengths, we find that point P divides AL in the ratio of 3:1. ### Final Answer Thus, point P divides AL in the ratio **3:1**. ---

To solve the problem, we need to determine the ratio in which point P divides line segment AL in the given parallelogram ABCD. Here’s a step-by-step solution: ### Step 1: Understand the Geometry We have a parallelogram ABCD. Point L divides side BC in the ratio 1:2, and point M divides side DC in the ratio 1:2. We need to find the ratio in which point P divides line segment AL, where AL intersects BD at point P. ### Step 2: Assign Coordinates To simplify the calculations, we can assign coordinates to the points: - Let A = (0, 0) ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • INTRODUCTION TO VECTORS

    CENGAGE ENGLISH|Exercise INTEGER TYPE|8 Videos
  • INTRODUCTION TO VECTORS

    CENGAGE ENGLISH|Exercise ARCHIVES SUBJECTIVE TYPE|9 Videos
  • INTRODUCTION TO VECTORS

    CENGAGE ENGLISH|Exercise REASONING TYPE|11 Videos
  • INTEGRALS

    CENGAGE ENGLISH|Exercise All Questions|764 Videos
  • INVERSE TRIGONOMETRIC FUNCTIONS

    CENGAGE ENGLISH|Exercise Archives (Numerical Value type)|2 Videos

Similar Questions

Explore conceptually related problems

ABCD is a parallelogram. L is a point on BC which divides BC in the ratio 1:2 . AL intersects BD at P.M is a point on DC which divides DC in the ratio 1 : 2 and AM intersects BD in Q. Point Q divides DB in the ratio

ABCD is a parallelogram. L is a point on BC which divides BC in the ratio 1:2 . AL intersects BD at P.M is a point on DC which divides DC in the ratio 1 : 2 and AM intersects BD in Q. PQ : DB is equal to

In DeltaABC , a point P on BC divided BC in the ratio 1:1. what is the line segment joining vertex A and P called ?

ABCD is parallelogram. If L and M are the middle points of BC and CD, then bar(AL)+bar(AM) equals

ABCD is a parallelogram of area 162 sq. Cm P is a point on AB such that AP : PB = 1 :2 Calculate The ratio of PA : DC.

The locus of a point which divides the join of A(-1,1) and a variable point P on the circle x^(2)+y^(2)=4 in the ratio 3:2 is

The diagonals of a parallelogram ABCD intersect at a point O. Through O, a line a drawn to intersect AD at P and BC at Q. Show that PQ divides the parallelogram into two parts of equal area.

The coordinates of a point which divides the join of points (3, 3, 7) and (8, 3, 1) internally in the ratio 2 : 1 is

The point which divides the line segment joining the points (8,–9) and (2,3) in ratio 1 : 2 internally lies in the

In A B C , P divides the side A B such that A P : P B=1:2 . Q is a point in A C such that P Q B C . Find the ratio of the areas of A P Q and trapezium B P Q C .