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If S1 is the sum of an AP of 'n' odd num...

If `S_1` is the sum of an AP of 'n' odd number of terms and `S_2` be the sum of the terms of series in odd places of the same AP then `S_1/S_2` =

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To solve the problem, we need to find the ratio \( \frac{S_1}{S_2} \) where \( S_1 \) is the sum of an arithmetic progression (AP) with \( n \) odd terms, and \( S_2 \) is the sum of the terms in the odd positions of the same AP. ### Step 1: Calculate \( S_1 \) The sum \( S_1 \) of an AP with \( n \) terms can be calculated using the formula: \[ S_1 = \frac{n}{2} \times (a_1 + a_n) ...
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