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If G is the geometric mean of xa n dy th...

If `G` is the geometric mean of `xa n dy` then prove that `1/(G^2-x^2)+1/(G^2-y^2)=1/(G^2)`

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To prove that \[ \frac{1}{G^2 - x^2} + \frac{1}{G^2 - y^2} = \frac{1}{G^2} \] where \( G \) is the geometric mean of \( x \) and \( y \), we start by noting that the geometric mean \( G \) is defined as: ...
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