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The first and second term of a G.P. are ...

The first and second term of a G.P. are `x^(-4) and x^(n)` respectively. If `x^(52)` is the `8^(th)` term, then find the value of n.

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To solve the problem, we need to find the value of \( n \) given the first term and second term of a geometric progression (G.P.) and the 8th term. ### Step-by-step Solution: 1. **Identify the Terms**: - The first term \( a_1 = x^{-4} \) - The second term \( a_2 = x^n \) - The 8th term \( a_8 = x^{52} \) 2. **Find the Common Ratio**: - The common ratio \( r \) of a G.P. can be calculated using the formula: \[ r = \frac{a_2}{a_1} = \frac{x^n}{x^{-4}} = x^{n + 4} \] 3. **Use the Formula for the nth Term**: - The formula for the nth term of a G.P. is given by: \[ a_n = a_1 \cdot r^{n-1} \] - For the 8th term: \[ a_8 = a_1 \cdot r^{7} \] - Substituting the values we have: \[ x^{52} = x^{-4} \cdot (x^{n + 4})^{7} \] 4. **Simplify the Equation**: - Simplifying the right side: \[ x^{52} = x^{-4} \cdot x^{7(n + 4)} \] - This can be rewritten as: \[ x^{52} = x^{-4 + 7(n + 4)} \] - Combine the exponents: \[ x^{52} = x^{7n + 28 - 4} = x^{7n + 24} \] 5. **Set the Exponents Equal**: - Since the bases are the same, we can set the exponents equal to each other: \[ 52 = 7n + 24 \] 6. **Solve for \( n \)**: - Rearranging the equation: \[ 7n = 52 - 24 \] \[ 7n = 28 \] \[ n = \frac{28}{7} = 4 \] ### Conclusion: The value of \( n \) is \( 4 \).

To solve the problem, we need to find the value of \( n \) given the first term and second term of a geometric progression (G.P.) and the 8th term. ### Step-by-step Solution: 1. **Identify the Terms**: - The first term \( a_1 = x^{-4} \) - The second term \( a_2 = x^n \) - The 8th term \( a_8 = x^{52} \) ...
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Knowledge Check

  • The first and second terms of a G.P are x^(-4) and x^(m) respectively. If its 8th term is x^(52) , then the value of m is

    A
    A. 8
    B
    B. 6
    C
    C. 4
    D
    D. 2
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