Home
Class 12
MATHS
Prove that the equation of the normal to...

Prove that the equation of the normal to `x^(2/3)+y^(2/3)=a^(2/3)` is `ycostheta-xsintheta=acos2theta,` where `theta` is the angle which the normal makes with the axis of `xdot`

Answer

Step by step text solution for Prove that the equation of the normal to x^(2/3)+y^(2/3)=a^(2/3) is ycostheta-xsintheta=acos2theta, where theta is the angle which the normal makes with the axis of xdot by MATHS experts to help you in doubts & scoring excellent marks in Class 12 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    CENGAGE ENGLISH|Exercise MATRIX MATCH TYPE|3 Videos

  • APPLICATION OF DERIVATIVES

    CENGAGE ENGLISH|Exercise ILLUSTRATION|62 Videos

  • 3D COORDINATION SYSTEM

    CENGAGE ENGLISH|Exercise DPP 3.1|11 Videos

  • APPLICATION OF INTEGRALS

    CENGAGE ENGLISH|Exercise All Questions|142 Videos

Similar Questions

Explore conceptually related problems

Equation of normal to x^(2)-4y^(2)=5 at theta=45^(@) is

Equation of normal to 9x^(2)-25y^(2)=225 at theta=pi//4 is

The normal at theta of the circle x^(2)+y^(2)=a^(2) is

Find the equation of normal to the curve x = a cos^(3)theta, y=b sin^(3) theta" at point "'theta'.

Find the equation of the normal to the circle x^(2) + y^(2)- 4x-6y+11=0 at (3,2) . Also find the other point where the normal meets the circle.

Find the equations of the tangent and the normal to the curve x=3costheta-cos^3theta,\ \ y=3sintheta-sin^3theta

Find the slope of the normal to the curve x=a\ cos^3theta , y=a\ sin^3theta at theta=pi/4 .

Find the equation of the normal at theta=(pi)/(3) to the hyperbola 3x^(2)-4y^(2)=12 .

Find the equations of the tangent and the normal to the curve x=theta+sintheta , y=1+costheta at theta=pi//2 at indicated points.

Find the equation of normal to the ellipse (x^(2))/(16)+(y^(2))/(9) = 1 at the point whose eccentric angle theta=(pi)/(6)

Home
Profile