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Young's modulus of steel is 19xx10^10 N/...

Young's modulus of steel is `19xx10^10 N/m^2`. Expres it indyne/cm^2. Here dyne is the CGS unit of force.

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To convert Young's modulus from N/m² to dyne/cm², we can follow these steps: ### Step-by-Step Solution: 1. **Identify the given value**: The Young's modulus of steel is given as \( 19 \times 10^{10} \, \text{N/m}^2 \). 2. **Convert Newtons to dynes**: ...
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Young 's modulus of steel is 2.0 xx 10^(11)N m//(2) . Express it is "dyne"/cm^(2) .

Young's modulus of steel is 1.9xx10^(11) N//m^2 When expressed is CGS units of dy"nes"// cm^2 it will be equal to (1N = 10^5dy"ne", 1 m^2 = 10^4 cm^2)

Knowledge Check

  • Young's modulus of steel is 1.9xx10^(11) N//m^2 When expressed is CGS units of dy"nes"// cm^2 it will be equal to (1N = 10^5dy"ne", 1 m^2 = 10^4 cm^2)

    A
    `1.9xx10^(10)`
    B
    `1.9xx10^(11)`
    C
    `1.9xx10^(12)`
    D
    `1.9xx10^(13)`

  • The area of a cross-section of steel wire is 0.1 cm^(-2) and Young's modulus of steel is 2 x 10^(11) N m^(-2) . The force required to stretch by 0.1% of its length is

    A
    1000 N
    B
    2000 N
    C
     4000 N
    D
    5000N

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    What will be the change in interatomic distance ( in Å ) of steel on applying a stress of 10^(9) N//m^(2) . The Young's modulus of steel is 2 xx 10^(11) N//m^(2) and the interatomic distance in steel is 2.8Å .

    A steel rod has a radius 10 mm and a length of 1.0 m. A force stretches it along its length and produces a strain of 0.32% . Young's modulus of the steel is 2.0xx10^(11Nm^(-2) . What is the magnitude of the force stretching the rod?

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    The diameter of a brass rod is 4 mm and Young's modulus of brass is 9 xx 10^(10) N//m^(2) . The force required to stretch by 0.1 % of its length is

    The Young's modulus of the material of a wire is 2xx10^(10) N m^(-2) If the elongation strain is 1% then the energy stored in the wire per unit volume is J m^(-3) is

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