Home
Class 11
PHYSICS
The distance travelled by a particle in ...

The distance travelled by a particle in time t is given by `s=(2.5m/s^2)t^2`. Find a. the average speed of the particle during the time 0 to 5.0 s, and b. the instantaneous speed ast t=5.0 is

Text Solution

Verified by Experts

a. The distance travelled during the 0 to 5.0 is
`s=(2.5m/s^2)(5.0)^2=62.5m`.
The average speed during this time is
`v_(av)=(62.5m)/(5s)=12.5m/s`
b. `s=(2.5 m/s^2)t^2`
or, `(ds)/(dt)=(2.5m/s^2)(2t)=(5.0 m/s^2)t`.
At t=5.0 s the speed is
`v=(ds)/(dt)=(5.0 m/s^2)(5.0s)=25m/s`.
Promotional Banner

Topper's Solved these Questions

  • REST AND MOTION : KINEMATICS

    HC VERMA ENGLISH|Exercise worked out Examples|20 Videos

  • REST AND MOTION : KINEMATICS

    HC VERMA ENGLISH|Exercise Objective -1|13 Videos

  • PHYSICS AND MATHEMATICS

    HC VERMA ENGLISH|Exercise Question for short Answer|14 Videos

  • ROTATIONAL MECHANICS

    HC VERMA ENGLISH|Exercise Questions for short Answer|21 Videos

Similar Questions

Explore conceptually related problems

The distance s of a particle in time t is given by s=t^3-6t^2-4t-8 . Its acceleration vanishes at t=

The distance covered by an object (in meter) is given by s=8 t^(3)-7t^(2)+5t Find its speed at t = 2 s.

The displacement (in metre) of a particle moving along X-axis is given by x=18t+5t^(2) . The average acceleration during the interval t_(1)=2s and t_(2)=4s is

Figure shows the speed versus time graph for a particle. Find the distance travelled by the particle during the time t=0 to t=3s.

The position (x) - time (t) graph for a particle moving along a straight line is shown in figure. The average speed of particle in time interval t = 0 to t = 8 s is

Fig. shows the graph of the x-coordinate of a particle going along the x-axis as a function of time. Find (a) the average velocity during 0 to 10 s, (b) instantaneous velocity at 2, 5, 8 and 12s.

Figure shows the graph of the x-coordinaste of a particle going along the X-axis as a function of time.Find a. te average velocity during 0 to 10s, b. instantaneous velocity at 2,5,8 and 12s.

The acceleration of a particle is given by a (t)=(3.00 m//s^(2)-(2.00 m/s^(3)) )t. (a) Find the initial speed v_(0) such that the particle will have the same x -coordinate at t =5.00 as it had at t=0. (b)What will be the velocity at t =5.00s?

Acceleration of a particle is given by a= 3t^(2)+2t +1 Where t is time . Find (i) its velocity at time t assuming velocity to be 10 m/s at t = 0. (ii) its position at time t assuming that the particle is at origin at t = 0. (iii) What is the average speed of the particle in the duration t = 0 to t = 1s? (iv) What is the average acceleration of the particle in the duration t = 0 to t = 1s?

The velocity of a particle is given by v=(2t^(2)-3t+10)ms^(-1) . Find the instantaneous acceleration at t = 5 s.