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A student says that he had applied a for...

A student says that he had applied a force `F=-ksqrtx` on a particle and the particle moved in simple harmonic motion. He refuses to tell whether k is a constant or not. Assume that he has worked only with positive x and no other force acted on the particle

A

As x increases k increaes

B

As x inceases k decreases

C

As x increases k remains constant

D

The motion cannot be simple harmonic

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the force applied to the particle and determine if it can lead to simple harmonic motion (SHM). The force given is \( F = -k \sqrt{x} \). ### Step 1: Understand the force equation The force acting on the particle is given by: \[ F = -k \sqrt{x} \] where \( k \) is a constant (or not) and \( x \) is the position of the particle. ### Step 2: Relate force to acceleration According to Newton's second law, the force can also be expressed as: \[ F = m a \] where \( m \) is the mass of the particle and \( a \) is its acceleration. ### Step 3: Express acceleration in terms of position In simple harmonic motion, the acceleration \( a \) can be expressed as: \[ a = -\omega^2 x \] where \( \omega \) is the angular frequency. Therefore, the force can also be written as: \[ F = -m \omega^2 x \] ### Step 4: Set the two expressions for force equal Since both expressions represent the same force acting on the particle, we can set them equal to each other: \[ -k \sqrt{x} = -m \omega^2 x \] ### Step 5: Rearrange the equation Removing the negative signs and rearranging gives: \[ k \sqrt{x} = m \omega^2 x \] ### Step 6: Solve for k Dividing both sides by \( \sqrt{x} \) (assuming \( x > 0 \)): \[ k = m \omega^2 \sqrt{x} \] ### Step 7: Analyze the relationship between k and x From the equation \( k = m \omega^2 \sqrt{x} \), we can see that \( k \) is directly proportional to \( \sqrt{x} \). This means that as \( x \) increases, \( k \) also increases. ### Conclusion Since we have established that \( k \) increases with \( x \), the correct option is: - As \( x \) increases, \( k \) increases. ### Final Answer The correct option is: **As x increases, k increases.** ---
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HC VERMA ENGLISH-SIMPLE HARMONIC MOTION-Objective -1
  1. A student says that he had applied a force F=-ksqrtx on a particle and...

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  2. A particle performing SHM takes time equal to T (time period of SHM) i...

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  3. A particle executing linear SHM. Its time period is equal to the small...

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  4. The displacement of a particle in simple harmonic motion in one time p...

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  5. The distance moved by a particle in simple harmonic motion in one time...

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  6. The average acceleration in one time period in a simple harmonic motio...

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  7. The motion of a particle is given by x=A sinomegat+Bcosomegat. The mot...

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  8. The displacement of a particle is given by vecr=A(vecicosomegat+vecjsi...

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  9. A particle moves on the X-axis according to the equation x=A+Bsinomega...

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  10. Figure represents two simple harmonic motions the parameter which has ...

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  11. The total mechanical energy of a spring mass system in simple harmonic...

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  12. The average energy in one time period in simple harmonic motion is

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  13. A particle executes simple harmonic motion with a frequency. (f). The ...

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  14. A particle executes simple harmonic motion under the restoring force p...

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  15. Two bodies A and B of equal mass are suspended from two separate massl...

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  16. A spring mass system oscillates with a frequency v. If it is taken in ...

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  17. A spring mass system oscillates in a car. If the car accelerates on a ...

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  18. A pendulum clock that keeps the correct time on the earth is taken to ...

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  19. A wall clock uses a vertical spring mass system to measure the time. E...

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  20. A pendulum clock keeping correct time is taken to high altitudes

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