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A vertical electric field of magnitude 4...

A vertical electric field of magnitude `4.00xx 10^5 NC^(-1)`. just prevents a water droplet of mass `1.000xx10^(-4) kg`from. falling., find the charge on the droplet.

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To find the charge on the water droplet that is just prevented from falling by the electric field, we can follow these steps: ### Step 1: Understand the forces acting on the droplet The water droplet is subject to two forces: 1. The gravitational force (weight) acting downward, given by \( F_g = mg \). 2. The electrostatic force acting upward, given by \( F_e = EQ \), where \( E \) is the electric field strength and \( Q \) is the charge on the droplet. ### Step 2: Set the forces equal to each other ...
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