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An electric current of 2.0 A passes thro...

An electric current of `2.0` A passes through a wire of resistance `25 Omega`. How much heat will be developed in 1 minute?

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To solve the problem of how much heat will be developed in a wire when an electric current passes through it, we can use Joule's law of heating. Here's a step-by-step solution: ### Step 1: Identify the given values - Current (I) = 2.0 A - Resistance (R) = 25 Ω - Time (t) = 1 minute = 60 seconds ### Step 2: Write the formula for heat produced According to Joule's law, the heat (H) produced in a resistor is given by the formula: \[ H = I^2 \times R \times t \] where: - \( H \) is the heat energy in Joules, - \( I \) is the current in Amperes, - \( R \) is the resistance in Ohms, - \( t \) is the time in seconds. ### Step 3: Substitute the values into the formula Now, substitute the values into the formula: \[ H = (2.0 \, \text{A})^2 \times (25 \, \Omega) \times (60 \, \text{s}) \] ### Step 4: Calculate \( I^2 \) Calculate \( I^2 \): \[ (2.0 \, \text{A})^2 = 4.0 \, \text{A}^2 \] ### Step 5: Substitute \( I^2 \) back into the equation Now substitute \( I^2 \) back into the equation: \[ H = 4.0 \, \text{A}^2 \times 25 \, \Omega \times 60 \, \text{s} \] ### Step 6: Multiply the values Now, calculate the product: \[ H = 4.0 \times 25 \times 60 \] First, calculate \( 4.0 \times 25 \): \[ 4.0 \times 25 = 100 \] Then multiply by 60: \[ 100 \times 60 = 6000 \] ### Step 7: State the final answer Thus, the heat developed in the wire in 1 minute is: \[ H = 6000 \, \text{Joules} \] ### Summary The heat developed in the wire when a current of 2.0 A passes through a resistance of 25 Ω for 1 minute is **6000 Joules**. ---

To solve the problem of how much heat will be developed in a wire when an electric current passes through it, we can use Joule's law of heating. Here's a step-by-step solution: ### Step 1: Identify the given values - Current (I) = 2.0 A - Resistance (R) = 25 Ω - Time (t) = 1 minute = 60 seconds ### Step 2: Write the formula for heat produced ...
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HC VERMA ENGLISH-THERMAL AND CHEMICAL EFFECT OF ELECTRIC CURRENT-Exercise
  1. An electric current of 2.0 A passes through a wire of resistance 25 Om...

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  2. A coil of resistance 100 Omega is connected across a battery of emf 6....

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  3. The specification on a heater coil is 250 V, 500 W. Calculate the resi...

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  4. A heater coil is to be constructed with a nichrome wire (rho = 1.0 xx ...

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  5. A bulb with rating 250V, 100W is connected to a power supply of 220 V ...

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  6. An electric bulb, when connected across a power supply of 220V, consum...

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  7. A servo voltage stabiliser restricts the voltage output to 220 V +- 1%...

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  8. An electric bulb marked 220 V, 100 W will get fused if it is made to c...

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  9. An immersion heater rated 1000 W, 220 V is used to heat 0.01 m^3 of wa...

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  10. An electric kettle used to prepare tea, takes 2 minutes to boil 4 cups...

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  11. The coil of an electric bulb takes 40 watts to start glowing. If more ...

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  12. The 2.0 Omega resistor show in figure is dipped into a calorimeter con...

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  13. The temperatures of the junctions of a bismuth-silver thermocouple are...

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  14. Find the thermo-emf developed in a copper-silver thermocopule when the...

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  15. Find the neutral temperatuer and inversion temperature of copper-iron ...

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  16. Find the charge required to flow through an electrolyte to liberate on...

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  17. Find the amount of silver liberated at cathode if 0.500 A of current i...

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  18. An electroplating unit plates 3.0 g of silver on a brass plate in 3.0 ...

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  19. Find the time requried to liberate 1.0 litre of hydrogen at STP in an...

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