For `3s` orbital of hydrogen atom, the normalised wave function is
`Psi_(3s)=(1)/((81)sqrt(3pi))((1)/(a_(o)))^(3//2)[27-(18r)/(a_(o))+(2r^(2))/(a_(o)^(2))]e^((-r)/(3a_(o)))`
If distance between the radial nodes is d, calculate rthe value of `(d)/(1.73a_(o))`

The wave function of 3s electron is given by Psi_(3s)=1/(81sqrt(3)prod)(1/a_(0))^(3//2)[27-18(r/a_(0))+2(r/a_(0))^(2)]e^(-r//3a_(0)) It has a node at r=r_(0) , Find out the relation between r_(0) and a_(0)

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :

Consider psi (wave function) of 2s atomic orbital of H-atom is- psi_(2s)=(1)/(4sqrt(2pia_(0)^(3//2)))[2-(r )/(a_(0))]e^.(r )/(2a_(0) Find distance of radial node from nucleous in terms of a_(0)

Consider psi (wave function) of 2s atomic orbital of H-atom is- psi_(2s)=(1)/(4sqrt(2pia_(0)^(3//2)))[2-(r )/(a_(0))]e^.(r )/(2a_(0) Find distance of radial node from nucleous in terms of a_(0)

(a) The wave function of an electron in 2s orbital in hydrogen atom is given below: psi_(2s)=1/(4(2pi)^(1//2))(z/a_(0))^(3//2)(2-r/a_(0))exp(-r//2a_(0)) where a_(0) is the radius. This wave function has a radial node at r=r_(0) . Express r_(0) in terms of a_(0) . (b) Calculate the wavelength of a ball of mass 100 g moving with a velocity of 100 ms^(-1) .

For a 3s - orbital, value of Phi is given by following realation: Psi(3s)=(1)/(9sqrt(3))((1)/(a_(0)))^(3//2)(6-6sigma+sigma^(2))e^(-sigma//2)," where " sigma=(2r.Z)/(3a_(0)) What is the maximum radial distance of node from nucleus?

For a 3s-orbital Phi(3s)=(1)/(asqrt(3))((1)/(a_(0)))^(3//2)(6-6sigma+sigma^(2))in^(-sigma//2) where sigma=(2rZ)/(3a_(sigma)) What is the maximum radial distance of node from nucleus?

For a 3s-orbital Phi(3s)=(1)/(asqrt(3))((1)/(a_(0)))^(3//2)(6-6sigma+sigma^(2))in^(-sigma//2) where sigma=(2rZ)/(3a_(sigma)) What is the maximum radial distance of node from nucleus?

If (1^(2)-a_(1))+(2^(2)-a_(2))+(3^(2)-a_(3))+…..+(n^(2)-a_(n))=(1)/(3)n(n^(2)-1) , then the value of a_(7) is

The first orbital of H is represented by: psi=(1)/(sqrtpi)((1)/(a_(0)))^(3//2)e^(-r//a_(0)) , where a_(0) is Bohr's radius. The probability of finding the electron at a distance r, from the nucleus in the region dV is :