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Which of the following conditions may le...

Which of the following conditions may lead to a non-spontaneous change?
a.`DeltaH " and "DeltaS " both "+ve`
b.`DeltaH=-ve,DeltaS=+ve`
c.`DeltaH=+ve,DeltaS=-ve`
d.`DeltaH=-ve,DeltaS=-ve`

A

`DeltaH " and "DeltaS " both "+ve`

B

`DeltaH=-ve,DeltaS=+ve`

C

`DeltaH=+ve,DeltaS=-ve`

D

`DeltaH=-ve,DeltaS=-ve`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which conditions may lead to a non-spontaneous change, we need to analyze the Gibbs free energy change (ΔG) using the equation: \[ \Delta G = \Delta H - T \Delta S \] Where: - ΔG = change in Gibbs free energy - ΔH = change in enthalpy - T = temperature in Kelvin - ΔS = change in entropy A reaction is spontaneous if ΔG is less than zero (ΔG < 0) and non-spontaneous if ΔG is greater than zero (ΔG > 0). ### Step-by-Step Solution: 1. **Analyze Option A: ΔH > 0 and ΔS > 0** - Here, both ΔH and ΔS are positive. - As temperature (T) increases, the term \(T \Delta S\) also increases. - Therefore, ΔG can be positive, leading to a non-spontaneous reaction at higher temperatures. 2. **Analyze Option B: ΔH < 0 and ΔS > 0** - ΔH is negative and ΔS is positive. - This means that ΔG will be negative at all temperatures because the negative ΔH will outweigh the positive \(T \Delta S\). - Hence, this condition leads to a spontaneous reaction. 3. **Analyze Option C: ΔH > 0 and ΔS < 0** - Here, ΔH is positive and ΔS is negative. - This means ΔG will be positive because both terms contribute to making ΔG positive. - Thus, this condition leads to a non-spontaneous reaction. 4. **Analyze Option D: ΔH < 0 and ΔS < 0** - In this case, ΔH is negative and ΔS is negative. - At low temperatures, the negative ΔH can make ΔG negative, but as temperature increases, the negative \(T \Delta S\) can lead to a positive ΔG. - Therefore, this condition can also lead to a non-spontaneous reaction at higher temperatures. ### Conclusion: The conditions that may lead to a non-spontaneous change are: - Option A: ΔH > 0 and ΔS > 0 - Option C: ΔH > 0 and ΔS < 0 - Option D: ΔH < 0 and ΔS < 0 Thus, the correct options that may lead to a non-spontaneous change are A, C, and D.

To determine which conditions may lead to a non-spontaneous change, we need to analyze the Gibbs free energy change (ΔG) using the equation: \[ \Delta G = \Delta H - T \Delta S \] Where: - ΔG = change in Gibbs free energy ...
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