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A balloon of diameter 21 meter weight 10...

A balloon of diameter 21 meter weight 100 kg. Calculate its pay-load, if it is filled with He at 1.0 atm and `27^(@)C`. Density of air is 1.2 kg `m^(-3)` . (Given : R=0.082 L atm `K^(-1)mol^(-1)`)

A

4952.42 kg

B

4932.42 kg

C

493.242 kg

D

none of these

Text Solution

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The correct Answer is:
To solve the problem of calculating the payload of a helium-filled balloon, follow these steps: ### Step 1: Calculate the Volume of the Balloon The balloon is spherical, and the volume \( V \) of a sphere is given by the formula: \[ V = \frac{4}{3} \pi r^3 \] Where \( r \) is the radius of the balloon. Given the diameter is 21 meters, the radius \( r \) is: \[ r = \frac{21}{2} = 10.5 \text{ meters} \] Now, substituting the radius into the volume formula: \[ V = \frac{4}{3} \pi (10.5)^3 \] Calculating \( V \): \[ V \approx \frac{4}{3} \times \frac{22}{7} \times 1157.625 \approx 4851.0 \text{ m}^3 \] ### Step 2: Convert Volume to Liters To convert the volume from cubic meters to liters, we use the conversion factor \( 1 \text{ m}^3 = 1000 \text{ L} \): \[ V = 4851.0 \text{ m}^3 \times 1000 = 4851000 \text{ L} \] ### Step 3: Calculate the Mass of Helium Using the Ideal Gas Law \( PV = nRT \), where: - \( P = 1.0 \text{ atm} \) - \( V = 4851.0 \text{ m}^3 \) - \( R = 0.0821 \text{ L atm K}^{-1} \text{ mol}^{-1} \) - \( T = 27^{\circ}C = 300 \text{ K} \) First, we need to convert the volume from cubic meters to liters: \[ V = 4851.0 \text{ m}^3 = 4851000 \text{ L} \] Now, substituting into the Ideal Gas Law: \[ n = \frac{PV}{RT} = \frac{(1.0)(4851000)}{(0.0821)(300)} \approx 196,000 \text{ moles} \] Next, calculate the mass of helium: \[ \text{Mass of He} = n \times \text{Molar mass of He} = 196000 \times 4 \approx 784000 \text{ g} = 784 \text{ kg} \] ### Step 4: Calculate the Total Mass of the Balloon and Helium The total mass \( M_{\text{total}} \) is the sum of the mass of the balloon and the mass of helium: \[ M_{\text{total}} = M_{\text{balloon}} + M_{\text{helium}} = 100 \text{ kg} + 784 \text{ kg} = 884 \text{ kg} \] ### Step 5: Calculate the Mass of Air Displaced The mass of air displaced can be calculated using the density of air: \[ \text{Density of air} = 1.2 \text{ kg/m}^3 \] \[ M_{\text{air displaced}} = \text{Density} \times V = 1.2 \text{ kg/m}^3 \times 4851.0 \text{ m}^3 \approx 5821.2 \text{ kg} \] ### Step 6: Calculate the Payload The payload \( P \) is given by the difference between the mass of air displaced and the total mass: \[ P = M_{\text{air displaced}} - M_{\text{total}} = 5821.2 \text{ kg} - 884 \text{ kg} \approx 4937.2 \text{ kg} \] ### Final Answer The payload of the balloon is approximately: \[ \text{Payload} \approx 4937.2 \text{ kg} \]

To solve the problem of calculating the payload of a helium-filled balloon, follow these steps: ### Step 1: Calculate the Volume of the Balloon The balloon is spherical, and the volume \( V \) of a sphere is given by the formula: \[ V = \frac{4}{3} \pi r^3 \] Where \( r \) is the radius of the balloon. Given the diameter is 21 meters, the radius \( r \) is: ...
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