Home
Class 12
PHYSICS
Two stars of masses 3 xx 10^(31) kg each...

Two stars of masses `3 xx 10^(31)` kg each, and at distance `2 xx 10^(11)` m rotate in a plane about their common centre of mass O. A meteorite passes through O moving perpendicular to the star's rotation plane. In order to escape from the gravitational field of this double star, the minimum speed that meteorite should have at O is (Take Graviational constant `G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)`)

A

`24 xx 10^(4) m//s`

B

`1.4 xx 10^(5) m//s`

C

`3.8 xx 10^(4) m//s`

D

`2.8 xx 10^(5) m//s`

Text Solution

AI Generated Solution

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • JEE MAINS

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise Chemistry|1 Videos

  • JEE MAIN

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise All Questions|452 Videos

  • JEE MAINS 2020

    JEE MAINS PREVIOUS YEAR ENGLISH|Exercise PHYSICS|250 Videos

Similar Questions

Explore conceptually related problems

Find the gravitational potential due to a body o fmass 10kg at a distance (i) 10m and (ii) 20 m from the body. Gravitational constant G = 6.67 xx 10^(-11) Nm^(2) kg^(-1) .

Calculate the gravitational force of attraction between two bodies of masses 40 kg and 80 kg separated by a distance 15 m. Take G= 6.7 xx 10^(-11) N m^2 kg^(-2)

Knowledge Check

  • Two stars of masses m_(1) and m_(2) distance r apart, revolve about their centre of mass. The period of revolution is :

    A
    `2pisqrt(r^3/(2G(m_1+m_2)))`
    B
    `2pisqrt((r^3(m_1+m_2))/(2G(m_1m_2)))`
    C
    `2pisqrt((2r^3)/(G(m_1+m_2)))`
    D
    `2pisqrt((r^3)/(G(m_1+m_2)))`

    • Similar Questions

    Explore conceptually related problems

    The centre of two identical spheres are 1.0 m apart . If the gravitational force between the spheres be 1.0 N , then what is the mass of each sphere ? (G = 6.67 xx 10^(-11) m^(3) kg^(-1) s^(-2)) .

    If the acceleration due to gravity on earth is 9.81 m//s^(2) and the radius of the earth is 6370 km find the mass of the earth ? (G = 6.67 xx 10^(-11) Nm^(2)//kg^(2))

    If the value of universal gravitational constant is 6.67xx10^(-11) Nm^2 kg^(-2), then find its value in CGS system.

    Two stars of masses m_(1) and m_(2) distance r apart, revolve about their centre of mass. The period of revolution is :

    Calculate the mass of sum if the mean radius of the earth's orbit is 1.5xx10^(8)km and G=6.67xx10^(-11)Nxxm^(2)//kg^(2)

    In a binary star system one star has thrice the mass of other. The stars rotate about their common centre of mass then :

    Find the mass of the earth from the following data. The period of lunar orbit around the earth is 27.3 days and radius of the orbit 3.9 xx 10^(5) km. G = 6.67 xx 10^(-11) Nm^(-2) kg^(-2) .

    Home
    Profile