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Which theory can explain bonding Ni ...

Which theory can explain bonding ` Ni ( CO ) _ 4 `

A

MOT

B

CFT

C

VBT

D

Werner's theory

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The correct Answer is:
To determine which theory can explain the bonding in nickel tetracarbonyl (Ni(CO)₄), we can analyze the characteristics of the compound and the theories available. ### Step-by-Step Solution: 1. **Identify the Compound**: - The compound in question is nickel tetracarbonyl, Ni(CO)₄. It consists of a nickel (Ni) atom bonded to four carbon monoxide (CO) ligands. 2. **Consider the Theories**: - The theories we need to evaluate are: - Molecular Orbital Theory (MOT) - Valence Bond Theory (VBT) - Crystal Field Theory (CFT) - Werner's Theory 3. **Analyze the Nature of CO Ligands**: - Carbon monoxide (CO) is a strong field ligand and is known to promote the pairing of electrons. This characteristic is crucial in determining the hybridization and geometry of the complex. 4. **Hybridization and Geometry**: - In Ni(CO)₄, the nickel atom undergoes sp³ hybridization due to the presence of four CO ligands. This results in a tetrahedral geometry for the complex. 5. **Magnetic Properties**: - Ni(CO)₄ is diamagnetic, meaning it has no unpaired electrons. This is consistent with the idea that all electrons are paired due to the strong field nature of the CO ligands. 6. **Bonding Mechanism**: - The bonding in Ni(CO)₄ involves sigma bonding and back-bonding. The CO ligands donate electron density to the nickel atom, forming sigma bonds. Additionally, there is back-bonding where the filled d-orbitals of nickel interact with the empty π* orbitals of CO, stabilizing the complex. 7. **Conclusion**: - Given the above analysis, Molecular Orbital Theory (MOT) provides the best explanation for the bonding in Ni(CO)₄. It accounts for the hybridization, geometry, and the nature of the bonding interactions (including back-bonding). ### Final Answer: The theory that can explain bonding in nickel tetracarbonyl (Ni(CO)₄) is **Molecular Orbital Theory (MOT)**.
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Knowledge Check

  • Ni(CO)_(4) is

    A
    tetrahedral
    B
    square planar
    C
    linear
    D
    octahedral .
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