The ionization energy of hydrogen atom is `1.312 xx 10^(6) J mol^(-1) ` calculate the energy require for jump of electron from n=1 to n=2

Options

A. `9.56 xx 10^(5) j//mol`
B. `7.56 xx 10^(5) j//mol`
C. `9.84 xx 10^(5) j//mol`
D. `8.51 xx 1 0^(5) j//mol`

Answer

C

Explanation

`Delta E= 1.312 xx 10^(5) ((1)/(n_(1)^(2)) -(1)/(n_(2)^(2))) mol^(-1)`
`=1.312 xx 10^(6) ((1)/(1)-(1)/(4))`
`=9.84 xx 10^(5) J mol^(-1)`