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The ionization energy of hydrogen ato...

The ionization energy of hydrogen atom is `1.312 xx 10^(6) J mol^(-1) ` calculate the energy require for jump of electron from n=1 to n=2

A

`9.56 xx 10^(5) j//mol`

B

`7.56 xx 10^(5) j//mol`

C

`9.84 xx 10^(5) j//mol`

D

`8.51 xx 1 0^(5) j//mol`

Text Solution

Verified by Experts

The correct Answer is:
C
`Delta E= 1.312 xx 10^(5) ((1)/(n_(1)^(2)) -(1)/(n_(2)^(2))) mol^(-1)`
`=1.312 xx 10^(6) ((1)/(1)-(1)/(4))`
`=9.84 xx 10^(5) J mol^(-1)`
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Knowledge Check

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    A
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