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Give calculation of gas constant R for unit of bar Lit `mol^(-1)K^(-1)` in ideal gas equation.

Text Solution

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R = 0.08314 bar L `mol^(-1)K^(-1)`.
pV = nRT and `R=(pV)/(nT)`
`R=(("1 bar")(22.71L))/((1mol)(273.15 K))`
where, p = 1 bar
V = 22.71 L
T = 273.15 K
n = 1 mole.
R = 0.083141 bar L `mol^(-1)K^(-1)`
`R=8.0314x10^(-2)` bar L `mol^(-1)K^(-1)`.
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Knowledge Check

  • What is the value of Gas constant R in Joule "Kelvin"^(-1) mol^(-1) ?

    A
    `0.0821`
    B
    `82.1`
    C
    `1.987`
    D
    `8.3144`

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