Given the standard electrode potentials,...

Given the standard electrode potentials,
`K^(+)//K=-2.93V,Ag^(+)//Ag=0.80V`
`Hg^(2+)//Hg=0.79V`
`Mg^(2+)//Mg=-2.37V,Cr^(3+)//Cr=-0.74V`
arrange these metals in their increasing order of reducing power.

Text Solution

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As reduction potential is more positive, then it is strong reducing agent. Increasing reduction potential series is : `K^(+)//K(-293V),Mg^(+2)//Mg(-2.37V),Cr^(3+)//Cr(-0.74V),Hg^(+2)//Hg(0.79V),Ag^(+)//Ag(0.80V)`
Increasing order of reducing power is as under :
Ag, Hg, Cr, Mg, k

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Which is increasing order of the reducing power of the following metals on the basis of standard electrode potential ? Ag^(+)//Ag=0.80 V " "Mg^(2+)//Mg=-2.37V Hg^(2+)//Hg=0.79V" "Cr^(3+)//Cr=-0.74V

`Hg lt Ag lt Mg lt Cr`

`Cr lt Mg lt Ag lt Hg`

`Mg lt Cr lt Hg lt Ag`

`Ag lt Hg lt Cr lt Mg`

If given are following standard electrodes potential, then find out standard potential of cell. [Zn^(+2)|Zn=-0.763V,Ag^(+)|Ag=+0.799V] .

0.562 V

1.562V

`2.560V`

`1.560V`

Standard reduction potential of Zn^(2+)//Zn,Ni^(2+)//Ni and Fe^(2+)//Fe are -0.76 V, -0.23 V and -0.44 V respectively. So in which condition reaction X+Y^(2+) to Y+X^(2+) would be spontaneous ?

`X=Ni,Y=Fe`

`X=Ni,Y=Zn`

`X=Fe,Y=Zn`

`X=Zn,Y=Ni`

Given the standard electrode potentials,
`K^(+)//K=-2.93V,Ag^(+)//Ag=0.80V`
`Hg^(2+)//Hg=0.79V`
`Mg^(2+)//Mg=-2.37V,Cr^(3+)//Cr=-0.74V`
arrange these metals in their increasing order of reducing power.

Text Solution

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Knowledge Check

Which is increasing order of the reducing power of the following metals on the basis of standard electrode potential ? Ag^(+)//Ag=0.80 V " "Mg^(2+)//Mg=-2.37V Hg^(2+)//Hg=0.79V" "Cr^(3+)//Cr=-0.74V

If given are following standard electrodes potential, then find out standard potential of cell. [Zn^(+2)|Zn=-0.763V,Ag^(+)|Ag=+0.799V] .

Standard reduction potential of Zn^(2+)//Zn,Ni^(2+)//Ni and Fe^(2+)//Fe are -0.76 V, -0.23 V and -0.44 V respectively. So in which condition reaction X+Y^(2+) to Y+X^(2+) would be spontaneous ?

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KUMAR PRAKASHAN-REDOX REACTIONS-SECTION-D (NCERT EXEMPLAR SOLUTION LONG ANSWER TYPE)

Given the standard electrode potentials, `K^(+)//K=-2.93V,Ag^(+)//Ag=0.80V` `Hg^(2+)//Hg=0.79V` `Mg^(2+)//Mg=-2.37V,Cr^(3+)//Cr=-0.74V` arrange these metals in their increasing order of reducing power.

Text Solution

Topper's Solved these Questions

Similar Questions

Knowledge Check

Which is increasing order of the reducing power of the following metals on the basis of standard electrode potential ? Ag^(+)//Ag=0.80 V " "Mg^(2+)//Mg=-2.37V Hg^(2+)//Hg=0.79V" "Cr^(3+)//Cr=-0.74V

If given are following standard electrodes potential, then find out standard potential of cell. [Zn^(+2)|Zn=-0.763V,Ag^(+)|Ag=+0.799V] .

Standard reduction potential of Zn^(2+)//Zn,Ni^(2+)//Ni and Fe^(2+)//Fe are -0.76 V, -0.23 V and -0.44 V respectively. So in which condition reaction X+Y^(2+) to Y+X^(2+) would be spontaneous ?

Similar Questions

KUMAR PRAKASHAN-REDOX REACTIONS-SECTION-D (NCERT EXEMPLAR SOLUTION LONG ANSWER TYPE)

Given the standard electrode potentials,
`K^(+)//K=-2.93V,Ag^(+)//Ag=0.80V`
`Hg^(2+)//Hg=0.79V`
`Mg^(2+)//Mg=-2.37V,Cr^(3+)//Cr=-0.74V`
arrange these metals in their increasing order of reducing power.