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19.5 g of benzene on burning in the free...

19.5 g of benzene on burning in the free supply of oxygen liberated 12.6 kJ of energy at constant pressure. Calculate the enthalpy of combustion of benzene. Write the thermochemical equation. 

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19.5 grams of benzene on burning liberated 126 kl. 78 grams of benzene on burning liberated 502 kJ.
The enthalpy of combustion of benzene is` -502 kJ mol ^(-1).` The thermochemical equation is given as,
`C _(6) H _(6(l)) + (15)/(2) O _(2(g)) to 6CO _(2(g)) + 3H_(2(g)) + 3H _(2) O _((l)), Delta H =-502 kJ mol ^(-1)`
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The combustion of one mole of benzene takes place at 298 and 1 atm. After combustion, CO_(2)(g) and H_(2)O(l) are produced and 3267.0 kJ of heat is liberated. Calculate the standard enthalpy of formation. triangle_f H^@ benzene. Standard enthalpies of formation of CO_2(g) and H_20(l) are -393,5 kJ mol ""^(-1) and "-285.83 kJ mol"^(-1) respectively.

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Knowledge Check

  • The heat of combustion of benzene at 27^@C and at constant volume is -3245 KJ. Then the heat of combustion of benzene at the same temperature and at constant pressure

    A
    `-3241.26 KJ`
    B
    `-3252.48 KJ`
    C
    `-3248.74 KJ`
    D
    `3248.74 KJ`

  • Change in enthalpy and change in internal energy are state functions. The value of DeltaH, DeltaU can be determined by using Kirchoff's equation. Calculate the heat of formation of methane, given that heat of formation of water = -286kJ mol^(-1) , heat of combustion of methane = -890kJ mol^(-1) heat of combustion of carbon = -393.5 kJ mol^(-1)

    A
    `90.5 kJ mol^(-1)`
    B
    `-240 kJ mol^(-1)`
    C
    `-75.5kJ mol^(-1)`
    D
    `95.6 kJmol^(-1)`

  • Change in enthalpy and change in internal energy are state functions. The value of DeltaH, Delta U can be determined by using Kirchoff's equation Calculate the heat of formation of methane, given that heat of formation of water= -286kJ mol^(-1) , heat of combustion of methane = -890kJ mol^(-1) heat of combustion of carbon = -393.5 kJ mol^(-1)

    A
    `90.5 kJ mol^(-1)`
    B
    `-240 kJ mol^(-1)`
    C
    `-75.5 kJ mol^(-1)`
    D
    `95.6 kJ mol^(-1)`

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