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The heat of combustion of benzene at 27^...

The heat of combustion of benzene at `27^@C` found by bomb calorimeter i.e., for the reaction `C_6H_6_((l)) +7 1/2O_(2(g)) + 6CO_(2(g)) +3H_2O_((l))` is `-780 K.Cal mol^(-1)`. The heat evolved on burning 39g of benzene in an open vessel will be

A

390 K.Cal

B

`780.9 K.Cal `

C

`390.45 K.Cal `

D

`780 K.Cal `

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • For the reaction CO_((g)) + (1)/(2) O_(2(g)), K_(1)//K_(c) is

    A
    RT
    B
    `(RT)^(-1)`
    C
    `(RT)^(-1//2)`
    D
    `(RT)^(1//2)`

  • At 27^@C the reaction, C_6H_(6(l)) + 15/2 O_(2(g)) to 6CO_(2(g)) + 3H_2O((l)) proceeds spontaneously because the magnitude of

    A
    `DeltaH = TDeltaS`
    B
    `DeltaH gt TDeltaS`
    C
    `DeltaH lt TDeltaS`
    D
    `DeltaH  gt 0` and `TDelta S lt 0`

  • Which of the following holds good to the laws of thermodynamics for the reaction ? C_2H_(4(g)) + 3O_(2(g)) to 2CO_(2(g)) + 2H_2O_((l))

    A
    `DeltaH= Delta E + RT`
    B
    `DeltaH = DeltaE - RT`
    C
    `DeltaH = DeltaE + 2RT`
    D
    `DeltaH = DeltaE - 2RT`

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    Which of the following holds good to the laws of thermodynamics for the reaction ? C_(2) H _(4 (g)) + 3O _(2 (g)) to 2 CO _(2(g)) + 2 H_(2) O _((l))

    2H_(2(g)) + O_(2(g)) rarr 2H_(2)O_((l)) , DeltaH= -ve and DeltaG= -ve . Then the reaction is

    For the reaction 2H_(2(g)) + o_(2(g)) rarr 2H_(2)O_((g)), Delta H^(@) = - 573.2 kJ . The heat of decomposition of water per mol is:

    Benzene burns in oxygen according to the equation 2C_(6)H_(6(l))+15O_(2(g))rarr12CO_(2(g))+6H_(2)O_((l)) . How many litres of oxygen are required at STP for the complete combustion of 39g of liquid benzene?

    CH_(4(g)) + 2O_(2(g)) rarr CO_(2(g)) + 2H_2O_((l)) DeltaH = -200 K.cal , now DeltaE Cal, now DeltaE for the same process at 300 K (in K.Cal)

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