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The number of electrons in M-shell of an...

The number of electrons in M-shell of an element with atomic number 24 is

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The correct Answer is:
3
Configuration (Z=33) `= 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^(10) 4p^3`
Each subshell has one orbital with m = 0
`therefore ` No. of electrons `=2xx 7 +1 = 15`
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The number of electrons present in M shell of aluminum atom:

The number of electrons in M shell is equal to the number of electrons in L shell for an element. Write the name, electronic configuration of that element and also write the values of four quantum numbers for the last electron.

Knowledge Check

  • The valence electron configuration of an element with atomic number 23 is

    A
    `3d^(5)`
    B
    `3d^(3) 4s^(2)`
    C
    `3d^(2) 4s^(1) 4p^(1)`
    D
    `3d^(2)4s^(2) 4p^(1)`

  • The valence electron configuration of an element with atomic number 23 is

    A
    `3d^(5)`
    B
    `3d^(5) 4s^(2)`
    C
    `3d^(2) 4s^(1) 4p^(1)`
    D
    `3d^(2) 4s^(2) 4p^(1)`

  • The valence electron configuration of an element with atomic number 23 is

    A
    `3d^(5)`
    B
    `3d^(3)4s^(2)`
    C
    `3d^(2)4s^(1)4p^(1)`
    D
    `3d^(2)4s^(2)4p^(1)`

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    In an atom the number of electrons in M - shell is equal to the number of electrons in the K and L - shell . Answer the question. Explanation : 1) Number of electrons in K-shell (1 s^(2)) = 2 Number of electrons in L-shell (2s^(2) sp^(6)) = 8 Total number of electrons in k & L shells = 10 2) Given that number of electrons in M-shell is equal to number of electrons in K& L- shells 3) Hence number of electrons in M-shell (3s^(2) 3p^(6) 3d^(2)) = 10 4) But , we know that before filling of 3d orbital 4s should be filled (4s^(2)) 5) So , electronic configuration is 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) 3d^(2) How many electrons are there in its outermost shell ?

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