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The n-factor of FeS2 during its oxidati...

The n-factor of `FeS_2` during its oxidation as `Fes_(2) rarr Fe_(2)O_3+SO_2`

A

10

B

11

C

2

D

8

Text Solution

Verified by Experts

The correct Answer is:
B
`Fe^(2+)overset((1))rarroverset(3+)(Fe )+e^(-)`
`S_2^(2-)rarr2SO_(2)+10C^(-)`
total = 11
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Knowledge Check

  • The number of electrons lost or gained during the change, Fe + H_(2)O rarr Fe_(3)O_4 + H_2

    A
    2
    B
    4
    C
    6
    D
    8

  • Which of the following are correct about the reaction, FeS_(2) + O_(2)rarrFe_(2)O_3 + SO_(2)

    A
    E.q. wt. of `FeS_2` is M/11
    B
    Eq. wt. of `SO_2` is M/5.5
    C
    S has -2 oxidation state in `FeS_2`
    D
    1 mole of `FeS_2` requires 7/4 mole of `O_2`

  • When FeS_2 is oxidized with sufficient O_2 then its oxidation product is found to be Fe_(2)O_3 and SO_2 if the molecular weight of FeS_(2), Fe_(2) O_3 and SO_2 are M. Ma and Mc, then which of the following statements are correct?

    A
    equivalent wt. of `FeS_2` is M/11
    B
    the molar ratio of `FeS_2` to `O_2` is 4:11
    C
    the molar ratio of `FeS_2` to `O_2` is 11:4
    D
    The molar ratio of `Fe_(2)O and SO_2` is 1:4

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    (A) For iron extraction usually Fe_(2) O_(3) is used but not FeS_(2) (R) Fe_(2) O_(3) does not produce polluting gas like SO_(2) but FeS_(2)

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