`A^(n+1)` is maximum oxidised by acidified `KMnO_(4)` solution into `AO_3^(-)` If 2.68 mmoles of `A^(+(n+1))` requires 32.16 mL of a 0.05 M acidified `KMnO_4` solution for complete oxidation, value of n is

Answer

A

Explanation

Change in oxidation no.of A = 4 – n
Change in oxidation no.of Mn = 5
`( 4 - n ) xx 2.68 = 5 xx 32.16 xx 0.05 :. n = 1 `