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When two liquids A and B are mixed, the ...

When two liquids A and B are mixed, the boiling point of the mixture become greater than the boiling points of pure liquid A and liquid B. The mixture is :

A

Ideal solution

B

Non ideal solution with negative deviation from Raoult’s Law

C

Non ideal solution with positive deviation from Raoult’s Law

D

Normal solution

Text Solution

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The correct Answer is:
To solve the question regarding the boiling point of a mixture of two liquids A and B, we need to analyze the behavior of the mixture in relation to Raoult's law and the concept of ideal and non-ideal solutions. ### Step-by-Step Solution: 1. **Understanding Raoult's Law**: Raoult's law states that the partial vapor pressure of each component in an ideal solution is equal to the vapor pressure of the pure component multiplied by its mole fraction in the mixture. For an ideal solution, the total vapor pressure is the sum of the partial pressures of the components. 2. **Identifying the Type of Solution**: The question states that the boiling point of the mixture is greater than the boiling points of pure liquids A and B. This indicates that the mixture does not behave like an ideal solution, as ideal solutions would not show such a significant change in boiling point. 3. **Analyzing the Boiling Point and Vapor Pressure Relationship**: The boiling point of a liquid is inversely related to its vapor pressure. If the boiling point of the mixture is higher, it implies that the vapor pressure of the mixture is lower than expected for an ideal solution. 4. **Determining the Type of Deviation**: Since the boiling point of the mixture is greater than that of the pure components, this indicates a negative deviation from Raoult's law. In a negative deviation, the interactions between the molecules of A and B are stronger than the interactions between the molecules of the pure components, leading to a lower vapor pressure and thus a higher boiling point. 5. **Conclusion**: Therefore, the mixture of liquids A and B is a non-ideal solution that exhibits negative deviation from Raoult's law. ### Final Answer: The mixture is a **non-ideal solution with negative deviation**. ---

To solve the question regarding the boiling point of a mixture of two liquids A and B, we need to analyze the behavior of the mixture in relation to Raoult's law and the concept of ideal and non-ideal solutions. ### Step-by-Step Solution: 1. **Understanding Raoult's Law**: Raoult's law states that the partial vapor pressure of each component in an ideal solution is equal to the vapor pressure of the pure component multiplied by its mole fraction in the mixture. For an ideal solution, the total vapor pressure is the sum of the partial pressures of the components. 2. **Identifying the Type of Solution**: The question states that the boiling point of the mixture is greater than the boiling points of pure liquids A and B. This indicates that the mixture does not behave like an ideal solution, as ideal solutions would not show such a significant change in boiling point. ...
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Knowledge Check

  • When two liquids A and B are mixed, their boiling points become greater than both of them. The mixture is :

    A
    ideal solution
    B
    non-ideal solution with negative deviation from Raoult's law
    C
    non-ideal solution with positive deviation from Raoult's law
    D
    normal solution
  • The boiling point of liquid is

    A
    affected by addition of soluble solid
    B
    increases with increase of pressure
    C
    both (a) and (b)
    D
    None of these
  • The boiling point of liquid argon is:

    A
    `-196^(@)C`
    B
    `-183^(@)C`
    C
    `-186^(@)C`
    D
    `-193^(@)C`
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