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BeF(2) is highly soluble in water, where...

`BeF_(2)` is highly soluble in water, whereas the fluorides of other alkaline earth metals are almost insoluble because 

A

`BeF_(2)` is ionic in nature

B

`BeF_(2)` is covalent in nature

C

Hydration energy of `BeF_(2)` is much higher than lattice energy

D

Lattice energy of `BeF_(2)` is much higher than its hydration energy

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Knowledge Check

  • Solubility of an ionic compound in water is mainly dependent on A) Lattice enthalpy " " B) Hydration enathalpy Both these factors oppose each other and the resultant of these determines thhe solubility of an ionic compound in water. If lattice enthalpy has greater value, the compound has greater value, the compound is less soluble. In case hydration enthaply has greater value, the compound is highly soluble is water BeF_(2) is soluble in water while fluorides of other alkalie earth metals are isoluble because of

    A
    Covalent nature of `BeF_(2)`
    B
    Ionic nature of `BeF_(2)`
    C
    Greater hydration enthalpy of `Be^(2+)` ion
    D
    Greater lattice enthalpy of `Be^(2+)` ion
  • Alkyl halides are almost insoluble in water because

    A
    They are ionic compounds
    B
    They have medium polarity
    C
    They do not form hydrogen bonds with water
    D
    A They have tetrahedral geometry
  • Beryllium differs from other alkaline earth metals because of

    A
    Small size and High EN
    B
    Large size and Low EN
    C
    Small size Low EN
    D
    Large size High EN
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