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In triangle ABC, angleA = angleC, AC = 5...

In `triangle ABC, angleA = angleC, AC = 5` and BC = 4. Then, the perimeter of `triangle` ABC is ..........

A

9

B

14

C

13

D

15

Text Solution

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The correct Answer is:
option 3
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Knowledge Check

  • In triangle ABC and triangle DEF, AB = DE, BC = EF and angleB = angleE . If the perimeter of triangle ABC is 20, then the perimeter of triangle DEF is ..........

    A
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    D
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    A
    `30.5 cm`.
    B
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    C
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    D
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    A
    `/_\ABC~=/_\DEF`
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    D
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