Find out the location of centre of mass of a uniform rod.

Explanation

Suppose a rod of mass M and length L is lying along the x-axis with its one end at x=0 and the other at x = L
Mass per unit length of the rod =`M/L`
Hence, mass of the element PQ of length dx situated at a distance V from the origin is dm =`M/L` dx
The coordinates of the element PQ are (x, 0,0). Therefore, x -coordinate of CM of the rod will be:
`x_(CM) = (int_(0)^(L)xdm)/(intdm) =(int_(0)^(L)(x)(M/Ldx))/M = I/L int_(0)^(L) xdx = L/2, y_(cm) =(int ydm)/(int dm)=0`