Home
Class 11
PHYSICS
An ideal gas of specific heat ratio gamm...

An ideal gas of specific heat ratio `gamma` with volume and pressure P is compressed to increase the pressure by `DeltaP`. If the change in volume is `Delta V_1` in an isothermal process and `Delta V_2` in an adiabatic process, then

A

`(Delta V_1)/(Delta V_2) = gamma`

B

`Delta V_1 gt Delta V_2`

C

`Delta V_2 gt Delta V_1`

D

`(Delta V_1)/(Delta V_2) = 1/gamma`

Text Solution

Verified by Experts

The correct Answer is:
A, B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMODYNAMICS

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE - II (LEVEL - II (INTEGER TYPE QUESTIONS)))|2 Videos

  • THERMODYNAMICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL - I (MAIN) STRAIGHT OBJECTIVE TYPE QUESTIONS)|29 Videos

  • THERMODYNAMICS

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE - II (LEVEL - II (STRAIGHT OBJECTIVE TYPE QUESTIONS)))|8 Videos

  • THERMAL PROPERTIES OF MATTER

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL - II) PRACTICE SHEET (ADVANCED) Integer/Subjective Type Questions|2 Videos

  • THERMOMETRY

    AAKASH SERIES|Exercise Numerical Exercise (LEVEL- 1)|11 Videos

Similar Questions

Explore conceptually related problems

An ideal gas is compressed to half of the volume. How much work is done if the process of compression is Isothermal

A piston divides a closed gas cylinder into two parts. Initially the piston is kept pressed such that one part has a pressure P and volume 5Vand the other part has pressure 8P and volume V, the piston is now left free. Find the new pressure and volume for the isothermal and adiabatic process.

Knowledge Check

  • For an ideal gas a) The change in internal energy in a constant-pressure process from temperature T_(1) to T_(2) is equal to nC_(V)(T_(2)-T_(1)) , where C_(V) is the molar heat capacity at constant volume and n is the number of moles of the gas b) The change in internal energy of the gas and the work done by the gas are equal in magnitude in an adiabatic process c) The internal energy does not change in an isothermal process d) No heat is added or removed in an adiabatic process

    A
    Only a, b are correct
    B
    only b, d are correct
    C
    only c, d are correct
    D
    all are correct

  • For an ideal gas a) The change in internal energy in a constant pressure process from temperature T_(1) to T_(2) is equal to nC_(v) (T‌_(2)-T_(1)) , where Cv is the molar heat capacity at constant volume and n is the number of moles of the gas b) The change in internal energy of the gas and the work done by the gas are equal in magnitude in an adiabatic process c) The internal energy does not change in an isothermal process d) No heat is added or removed in an adiabatic process

    A
    only a, b are correct
    B
    only b, d are correct
    C
    only c, d are correct
    D
    all are correct

  • For a gas if ratio of specific heats at constant pressure and volume is gamma then value of degrees of freedom is

    A
    `(3gamma-1)/(2gamma-1)`
    B
    `(2)/(gamma-1)`
    C
    `(9)/(2)(gamma-1)`
    D
    `(25)/(2)(gamma-1)`

    • Similar Questions

    Explore conceptually related problems

    A piston divides a closed gas cylinder into two parts. Initially the piston is kept pressed such that one part has a pressure P and volume 5V and the other part has pressure 8P and volume V, the piston is now left free. Find the new pressure and volume for the isothermal and adiabatic process. ( gamma = 1.5).

    The pressure P and volume V of an ideal gas both increase in a process

    Diatomic gas at pressure .P. and volume .V. is compressed adiabatically to 1/32 times the orginal volume. Then the final pressure is

    C_v and C_p denote the molar specific heat capacities of a gas at constant volume and constant pressure, respectively. Then

    The pressure P and volume V of an ideal gas both increase in a process

    Home
    Profile