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Nitrobenzene does not undergo Friedel-Cr...

Nitrobenzene does not undergo Friedel-Crafts alkylation. Give reasons.

Text Solution

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Due to powerful electron withdrawing effect of the `-NO_(2)` group, the benzene ring in `C_(6)H_(5)NO_(2)` is deactivated towards Friedel Craft’s alkylation and hence it is used as a solvent in many Fridel-Craft’s reaction.
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Knowledge Check

  • The Friedel-Crafts alkylation...

    A
    Works well for primary chlorides
    B
    Works very well for tertiary chlorides
    C
    Works very well for acyl chlorides
    D
    Works very well without catalyst
  • In Friedal-Craft's alkylation, catalyst is

    A
    Anhydrous `ZnCl_(2)`
    B
    Anhydrous `AlCl_(3)`
    C
    Trialkyl carbonium ion
    D
    Alkyl halide
  • In Friedal-Craft's alkylation, catalyst is

    A
    Anhydrous `ZnCl_2`
    B
    Anhydrous `AICI_3`
    C
    Trialkyl carbonium ion
    D
    Alkyl halide
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    Aniline does not undergo Friedel - Crafts reaction. Justify.

    Which of the following halides would undergo Friedel-Crafts alkylation without rearrangement?

    A benzene ring deactivated by strong and moderate electron withdrawing group that is, any meta directing group, is not electron rich enough to undergo Friedel-Crafts reactions. Friedel-Crafts reaction also do not occur with NH, group as it react with AlCl, and produce deactivating group Which of the following compounds undergo Friedel-Crafts alkylation reaction?

    Which of the following aromatic compounds undergoes Friedel-Crafts alkylation with methyl chloride and aluminum chloride?

    Why aryl haides and vinyl halides cannot be used in Friedel-Crafts alkylation reaction?