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A person stands in contact against a wal...

A person stands in contact against a wall of cylindrical drum of radius r , rotating with an angular velocity `omega ` . If is the coefficient of friction between the wall and the person, the minimum rotational speed which enables the person to remain stuck to the wall is

A

`sqrt((g//mu r)) `

B

`g//sqrt(mur)`

C

`sqrt((mur)/(g))`

D

`sqrt((gr)/(mu))`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • A person stands in contact against a wall of cylindrical drum of radius r, rotating with an angular velocity omega . If mu is the coefficient of friction between the wall and the person, the minimum rotational speed which enables the person to remain stuck to the wall is

    A
    `sqrt(g//mur)`
    B
    `g//sqrt(mu r)`
    C
    `sqrt((mu r)/(g))`
    D
    `sqrt((gr)/(mu))`

  • A ring of radius R is first rotated with an angular velocity omega_(0) and then carefully placed on a rough horizontal surface. The coefficient of friction between the surface and the ring is mu . Time after which its angular speed in reduced to half is

    A
    `(omega_(0)mu R)/(2g)`
    B
    `(omega_(0)mu R)/(2mu R)`
    C
    `(2omega_(0)R)/(mu g)`
    D
    `(omega_(0)R)/(2mu g)`

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    B
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