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A circular disk of moment of inertia I(t...

A circular disk of moment of inertia `I_(t)` is rotating in a horizontal plane , about its symmetry axis , with a constant angular speed `omega_(i)` . Another disk of moment of inertia `I_(b)` is dropped coaxially onto the rotating disk . Initially the second disk has zero angular speed . eventually both the disks rotate with a constant angular speed `omega_f` . The energy lost by the initially rotating disc to friction is

A

`(1)/(2) (I_(b)^(2))/((I_(t) + I_(b))) omega_(i)^(2)`

B

`(1)/(2) (I_(t)^(2))/((I_(i) + I_(b)))"" omega_(i)^(2)`

C

`(I_(b) - I_(t))/((I_(t) + I_(b))) "" omega_(i)^(2)`

D

`(1)/(2) (I_(b) I_(t))/((I_(t) + I_(b))) "" omega_(i)^(2)`

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The correct Answer is:
D
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