The pathway of respiration common in all living organisms is `ul(x)`, it occurs in the `ul(y)` and the products formed are two molecules of `ul(Z)`. Identify X,Y and Z in the above paragraph and select the correct answer.

Options

A. `{:(X,Y,Z),(EMP "pathyway","mitochondrion","pyruvic acid"):}`
B. `{:(X,Y,Z),(EMP "pathyway","cytoplasm","pyruvic acid"):}`
C. `{:(X,Y,Z),("Krebs' cycle","cytoplasm","acetyl CoA"):}`
D. `{:(X,Y,Z),("Krebs' cycle","mitochondrion","acetyl CoA"):}`

Answer

To solve the question, we need to identify the components X, Y, and Z based on the information provided in the question regarding the common pathway of respiration in all living organisms.

### Step-by-Step Solution:

1. **Identify X (the pathway of respiration common in all living organisms)**:
- The question states that the pathway of respiration common in all living organisms is X. The common pathway for respiration that occurs in both aerobic and anaerobic organisms is known as the **EMP pathway**, which is also referred to as **glycolysis**.

2. **Identify Y (the location where this pathway occurs)**:
- The question specifies that this pathway occurs in Y. Glycolysis occurs in the **cytoplasm** of the cell. This is true for all living organisms, including prokaryotes (like bacteria) where organelles are absent.

3. **Identify Z (the products formed)**:
- The final part of the question mentions that the products formed are two molecules of Z. During glycolysis, one molecule of glucose is converted into **two molecules of pyruvic acid**. Therefore, Z is **pyruvic acid**.

### Conclusion:
- Based on the analysis:
- X = EMP pathway (or glycolysis)
- Y = Cytoplasm
- Z = Pyruvic acid

The correct answer is the second option: **EMP pathway, cytoplasm, pyruvic acid**.