A galvanic cell has electrical potential of 1.1 V . If an opposing potential of 1.1 V is applied to this cell, what will happen to the cell reaction and current flowing through the cell ?

Options

A. The reaction stops and no current flows through the cell.
B. The reaction continuous but current flows in opposite direction.
C. The concentration of reactants becomes unity and current flows from cathode to anode.
D. The cell does not function as a galvanic cell and zinc is deposited on zinc plate.

Explanation

To solve the problem regarding the galvanic cell with an electrical potential of 1.1 V and an opposing potential of 1.1 V, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values:**
- The electrical potential of the galvanic cell (E_cell) = 1.1 V
- The opposing potential applied (E_opposing) = 1.1 V

2. **Calculate the Net Potential:**
- To find the net potential acting on the cell, we subtract the opposing potential from the cell's potential:
\[ \text{Net Potential} = E_{\text{cell}} - E_{\text{opposing}} = 1.1 \, \text{V} - 1.1 \, \text{V} = 0 \, \text{V} \]

3. **Determine the Effect on the Cell Reaction:**
- When the net potential is 0 V, it indicates that there is no driving force for the cell reaction to proceed. Therefore, the cell reaction will stop.

4. **Analyze the Current Flow:**
- Since the cell reaction has stopped, there will be no movement of electrons, which means that the current flowing through the cell will also be zero.

### Conclusion:
- The cell reaction will stop, and no current will flow through the cell.

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