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The rate constant is given by the equati...

The rate constant is given by the equation `k = P.Ze^(-E_(a)//RT)`. Which factor should register a decrease for the reaction to proceed more rapidly?

A

T

B

Z

C

E

D

pressure.

Text Solution

Verified by Experts

The correct Answer is:
C

Lower the activation energy, faster is the reaction.
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In the Arrhenius equation: k = A exp(-E_(a)//RT) , the rate constant

A colliison between reactant molecules must occur with a certain minimum energy before it is effective in yielding Product molecules. This minimum energy is called activation energy E_(a) Large the value of activation energy, smaller the value of rate constant k . Larger is the value of activation energy, greater is the effect of temperature rise on rate constant k . E_(f) = Activation energy of forward reaction E_(b) = Activation energy of backward reaction Delta H = E_(f) - E_(b) E_(f) = threshold energy The rate constant of a certain reaction is given by k = Ae^(-E_(a)//RT) (where A = Arrhenius constant). Which factor should be lowered so that the rate of reaction may increase?

Knowledge Check

  • The temperature dependence of the rate of a chemical reaction is given by arrhenius equation, k = Ae^(-Ea//RT) . Which of the following graphs will be a striaght line?

    A
    In A vs 1/T
    B
    In A vs `E_(a)`
    C
    In K vs 1/T
    D
    In k vs `-E_(a) //R`
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    Rate of reaction is given by the eqution : Rate = k[A]^(2)[B] . What are the units for the rate and rate constant for the reaction?

    Arrhenius studies the effect of temperature on the rate of a reaction and postulted that rate constant varies with temperature exponentially as k=Ae^(E_(a)//RT) . Thuis method is generally used for finding the activation energy of a reaction. Keeping temperature constant, the effect of catalyst on the activation energy has also been studied. The pre-exponetial factor in the Arrhenius equation of a first order reaction has the unit :

    Arrhenius studies the effect of temperature on the rate of a reaction and postulted that rate constant varies with temperature exponentially as k=Ae^(E_(a)//RT) . Thuis method is generally used for finding the activation energy of a reaction. Keeping temperature constant, the effect of catalyst on the activation energy has also been studied. If the rate of reaction doubles for 10^(@)C rise of temperature form 290K to 300K, the activation energy of the reaction will be approximately :

    Arrhenius studies the effect of temperature on the rate of a reaction and postulted that rate constant varies with temperature exponentially as k=Ae^(E_(a)//RT) . Thuis method is generally used for finding the activation energy of a reaction. Keeping temperature constant, the effect of catalyst on the activation energy has also been studied. If x is the fraction of molecules having energy greater than E_(a) it will be given by :

    The rate of reaction increases isgnificantly with increase in temperature. Generally, rate of reactions are doubled for every 10^(@)C rise in temperature. Temperature coefficient gives us an idea about the change in the rate of a reaction for every 10^(@)C change in temperature. "Temperature coefficient" (mu) = ("Rate constant of" (T + 10)^(@)C)/("Rate constant at" T^(@)C) Arrhenius gave an equation which describes aret constant k as a function of temperature k = Ae^(-E_(a)//RT) where k is the rate constant, A is the frequency factor or pre-exponential factor, E_(a) is the activation energy, T is the temperature in kelvin, R is the universal gas constant. Equation when expressed in logarithmic form becomes log k = log A - (E_(a))/(2.303 RT) Activation energies of two reaction are E_(a) and E_(a)' with E_(a) gt E'_(a) . If the temperature of the reacting systems is increased form T_(1) to T_(2) ( k' is rate constant at higher temperature).

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