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Which of the following pairs of ions hav...

Which of the following pairs of ions have the same electronic configuration A)`Cr^(+3),Fe^(+3)` B)`Fe^(+3),Mn^(+2)` C)`Fe^(+3),Co^(+3)` D)`Sc^(+3),Cr^(+3)`

A

`Cu^(2+),Cr^(2+)`

B

`Fe^(3+),Mn^(2+)`

C

`Co^(3+),Ni^(3+)`

D

`Sc^(3+),Cr^(3+)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which pairs of ions have the same electronic configuration, we will analyze the electronic configurations of each ion step by step. ### Step 1: Determine the electronic configuration of Cr^(+3) - Neutral Chromium (Cr) has an atomic number of 24. - The electronic configuration of neutral Cr is: \[ \text{Cr}: [Ar] 3d^5 4s^1 \] - To find the configuration of Cr^(+3), we remove 3 electrons. The 4s electron is removed first, followed by 2 electrons from the 3d subshell: \[ \text{Cr}^{+3}: 3d^3 \] ### Step 2: Determine the electronic configuration of Fe^(+3) - Neutral Iron (Fe) has an atomic number of 26. - The electronic configuration of neutral Fe is: \[ \text{Fe}: [Ar] 3d^6 4s^2 \] - For Fe^(+3), we remove 3 electrons (2 from 4s and 1 from 3d): \[ \text{Fe}^{+3}: 3d^5 \] ### Step 3: Determine the electronic configuration of Mn^(+2) - Neutral Manganese (Mn) has an atomic number of 25. - The electronic configuration of neutral Mn is: \[ \text{Mn}: [Ar] 3d^5 4s^2 \] - For Mn^(+2), we remove 2 electrons from the 4s subshell: \[ \text{Mn}^{+2}: 3d^5 \] ### Step 4: Determine the electronic configuration of Co^(+3) - Neutral Cobalt (Co) has an atomic number of 27. - The electronic configuration of neutral Co is: \[ \text{Co}: [Ar] 3d^7 4s^2 \] - For Co^(+3), we remove 3 electrons (2 from 4s and 1 from 3d): \[ \text{Co}^{+3}: 3d^6 \] ### Step 5: Determine the electronic configuration of Sc^(+3) - Neutral Scandium (Sc) has an atomic number of 21. - The electronic configuration of neutral Sc is: \[ \text{Sc}: [Ar] 3d^1 4s^2 \] - For Sc^(+3), we remove 3 electrons (2 from 4s and 1 from 3d): \[ \text{Sc}^{+3}: 3d^0 \] ### Summary of Electronic Configurations - **Cr^(+3)**: 3d^3 - **Fe^(+3)**: 3d^5 - **Mn^(+2)**: 3d^5 - **Co^(+3)**: 3d^6 - **Sc^(+3)**: 3d^0 ### Conclusion From the above calculations, we can see that: - **Pair A (Cr^(+3), Fe^(+3))**: Different configurations (3d^3 vs 3d^5) - **Pair B (Fe^(+3), Mn^(+2))**: Same configuration (3d^5 vs 3d^5) - **Pair C (Fe^(+3), Co^(+3))**: Different configurations (3d^5 vs 3d^6) - **Pair D (Sc^(+3), Cr^(+3))**: Different configurations (3d^0 vs 3d^3) Thus, the correct answer is **B) Fe^(+3), Mn^(+2)**.
To determine which pairs of ions have the same electronic configuration, we will analyze the electronic configurations of each ion step by step. ### Step 1: Determine the electronic configuration of Cr^(+3) - Neutral Chromium (Cr) has an atomic number of 24. - The electronic configuration of neutral Cr is: \[ \text{Cr}: [Ar] 3d^5 4s^1 \] ...
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