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When aqueous solution of potassium fluor...

When aqueous solution of potassium fluoride is added to the blue coloured aqueous `CuSO_(4)` solution , a green precipitate is formed . This observation can be explained as follows .

A

On adding `KF , H_(2)O` being weak field ligand is replaced by `F^(-)` ions forming `[CuF_(4)]^(2-)` which is green in colour .

B

Potassium is coordinated to `[Cu(H_(2)O)_(4)]^(2+)` ion present in `CuSO_(4)` and gives green colour .

C

On adding `KF , Cu^(2+)` are replaced by `K^(+)` forming a green complex .

D

Blue colour of `CuSO_(4)` and yellow colour of KF form green colour on mixing .

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To explain the observation that a green precipitate is formed when an aqueous solution of potassium fluoride (KF) is added to a blue-colored aqueous solution of copper sulfate (CuSO₄), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Components:** - We have two solutions: potassium fluoride (KF) and copper sulfate (CuSO₄). - CuSO₄ in aqueous solution is blue due to the presence of copper(II) ions (Cu²⁺). 2. **Understand the Role of Water:** - In aqueous solution, CuSO₄ dissociates into Cu²⁺ and SO₄²⁻ ions. - The copper(II) ions are surrounded by water molecules, forming a complex called tetra-aqua copper(II) [Cu(H₂O)₄]²⁺, which is blue in color. 3. **Introduce Potassium Fluoride:** - When potassium fluoride is added to this solution, the fluoride ions (F⁻) from KF act as ligands. - Fluoride is a stronger ligand compared to water. 4. **Ligand Exchange Reaction:** - Due to the stronger ligand nature of fluoride ions, they can replace the water molecules in the tetra-aqua complex. - The reaction can be represented as: \[ [Cu(H₂O)₄]^{2+} + 4F^{-} \rightarrow [CuF₄]^{2-} + 4H₂O \] - This results in the formation of the tetrafluorocuprate(II) complex, [CuF₄]²⁻. 5. **Color Change:** - The tetrafluorocuprate(II) complex [CuF₄]²⁻ is green in color. - Thus, the addition of KF leads to a color change from blue (due to Cu²⁺ in water) to green (due to [CuF₄]²⁻). 6. **Conclusion:** - The formation of the green precipitate can be attributed to the ligand exchange where water is replaced by fluoride ions, resulting in a new complex that exhibits a different color.

To explain the observation that a green precipitate is formed when an aqueous solution of potassium fluoride (KF) is added to a blue-colored aqueous solution of copper sulfate (CuSO₄), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Components:** - We have two solutions: potassium fluoride (KF) and copper sulfate (CuSO₄). - CuSO₄ in aqueous solution is blue due to the presence of copper(II) ions (Cu²⁺). ...
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