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[Fe(CN)(6)]^(4-) and [Fe(H(2)O)(6)]^(2+)...

`[Fe(CN)_(6)]^(4-)` and `[Fe(H_(2)O)_(6)]^(2+)` are of different colours in dilute solutions why?

A

`CN^(-)` is a strong field ligand and `H_(2)O` is a weak field ligand hence magnitude of CFSE is different

B

both `CN^(-)` and `H_(2)O` absorb same wavelength of energy

C

complexes of weak field ligands are generally colourless

D

the sizes of `CN^(-)` and `H_(2)O` are different hence their colours are also different .

Text Solution

AI Generated Solution

The correct Answer is:
To understand why the complexes \([Fe(CN)_{6}]^{4-}\) and \([Fe(H_{2}O)_{6}]^{2+}\) exhibit different colors in dilute solutions, we can break down the explanation into several steps: ### Step-by-Step Solution: 1. **Identify the Complexes**: - We have two complexes: \([Fe(CN)_{6}]^{4-}\) and \([Fe(H_{2}O)_{6}]^{2+}\). - Both complexes contain iron (Fe) in the +2 oxidation state. 2. **Determine the Ligands**: - The ligand in the first complex is cyanide (\(CN^{-}\)), and in the second complex, it is water (\(H_{2}O\)). - It is important to note that these ligands have different field strengths. 3. **Classify the Ligands**: - Cyanide (\(CN^{-}\)) is classified as a strong field ligand. - Water (\(H_{2}O\)) is classified as a weak field ligand. 4. **Crystal Field Theory**: - According to crystal field theory, ligands cause the d-orbitals of the central metal ion (Fe in this case) to split into different energy levels. - For octahedral complexes, the d-orbitals split into two sets: \(t_{2g}\) (lower energy) and \(e_g\) (higher energy). 5. **Crystal Field Splitting Energy (\(\Delta\))**: - The splitting energy (\(\Delta\)) is higher for strong field ligands compared to weak field ligands. - Therefore, in \([Fe(CN)_{6}]^{4-}\), the crystal field splitting energy is greater than in \([Fe(H_{2}O)_{6}]^{2+}\). 6. **Absorption of Light**: - The color of a complex is determined by the wavelengths of light it absorbs. The energy difference between the split d-orbitals corresponds to specific wavelengths of light. - Since \([Fe(CN)_{6}]^{4-}\) has a higher \(\Delta\), it absorbs light of a different wavelength compared to \([Fe(H_{2}O)_{6}]^{2+}\). 7. **Resulting Colors**: - Because the two complexes absorb different wavelengths of light, they will appear as different colors in dilute solutions. ### Conclusion: The difference in colors between \([Fe(CN)_{6}]^{4-}\) and \([Fe(H_{2}O)_{6}]^{2+}\) arises from the different crystal field splitting energies caused by the strong field ligand \(CN^{-}\) and the weak field ligand \(H_{2}O\).
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