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The oxidation state of chromium in Cr(CO...

The oxidation state of chromium in `Cr(CO)_(6)` is

A

covalent bonding

B

coordinate bonding

C

synergic bonding

D

ionic bonding

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The correct Answer is:
To determine the oxidation state of chromium in the complex `Cr(CO)_(6)`, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Ligands and Their Charges**: - The ligand in the complex is CO (carbon monoxide), which is a neutral ligand. This means it has a charge of 0. 2. **Set Up the Equation**: - Let the oxidation state of chromium (Cr) be represented as X. Since there are 6 CO ligands, we can express the total contribution of the ligands to the oxidation state as 6 multiplied by the charge of CO, which is 0. - Therefore, we can write the equation: \[ X + 6 \times 0 = 0 \] 3. **Solve for X**: - Simplifying the equation gives: \[ X + 0 = 0 \] - Thus, we find: \[ X = 0 \] 4. **Conclusion**: - The oxidation state of chromium in `Cr(CO)_(6)` is 0. ### Final Answer: The oxidation state of chromium in `Cr(CO)_(6)` is 0.
To determine the oxidation state of chromium in the complex `Cr(CO)_(6)`, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Ligands and Their Charges**: - The ligand in the complex is CO (carbon monoxide), which is a neutral ligand. This means it has a charge of 0. 2. **Set Up the Equation**: ...
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  • Oxidation state of iron in Fe(CO)_(4) is

    A
    `+1`
    B
    `-1`
    C
    `+2`
    D
    0

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